Ignoring the fact that BeH2 decomposes in water and theoretically stayed intact you would not expect hydrogen bonds as Be is not electronegative enough.
The chemical formula for Barium Hydride is BaH2. Ba = Barium H = Hydrogen Its molecular mass is 139.34288 g/mol.
About this type of question: My answer is that beryllium is small in size. So, the charge density (charge/radius) is extremely high. So, the force of attraction between the electrons in orbitals and proton in nucleus is very strong. When beryllium is encountered with the other elements (i.e. chlorine), the electrons cannot loss to environment(due to strong force of attraction), but the beryllium will be polarised to become positively charge and hence attract the electron from other elements to form the covalent compound (BeCl2 which is Cl-Be-Cl). So the beryllium hydride is a polar covalently bonded compound.
The diatomic molecules are linear molecules. Other examples of linear molecules include BeH2, CO2, and HCN.
CH4 is symbol for Methane.It is non polar.
For example nitric oxide (NO) and beryllium hydride (BeH2) have linear molecules.
Sulfur is in period 3 and has 6 valence electrons. The expected fluoride would be SF2, SF^ a very stable compound is surprisoing. The bonding in SF6 has been described in a number of ways- one is that there is sp3d2 hybridisation and there are 6 equivalent 2 electron 2 center bonds. Other descriptions involve resonance of ionic canonicals where the octet is preserved. Yet another description is "hypervalency" involving 3 centre bonds. With BeH2 the situation is different, in this there are not enough electrons to form an octet. Some call this electron deficiency. In BeH2 each Be is surrounded by 4 hydrogen atoms, and there 4 BeHBe bonds- 3 center 2 electron. These are similar to bonds in B2H6. The octet rule is a guideline- it has proved to be remarkably useful- but as someone said ".. in inorganic chemistry the rule is that there are no rules"
Beryllium is covalent and polymeric. Each beryllium atom is bonded to four hydrogen atoms and each hydrogen atoms forms two bonds as it is bridiging two Be atoms. Since Be has two valence electrons and H only one, it is apparent that there are not enough electrons to form the usual electron pair bonds in which two electrons are shared between two atoms. Instead of this , three-center bonds are formed in which a 'banana-shaped' molecular orbital covers three atoms BE...H...Be, anc contains two electrons.The monomeric molecule BeH2, if formed with normal bonds, would have only four electrons in the outer shell of the beryllium atom and would be electron deficient. This would make the molecule very unstable; that is why BeH2 exists as polymer.
It is an ionic solid.
The chemical formula for Barium Hydride is BaH2. Ba = Barium H = Hydrogen Its molecular mass is 139.34288 g/mol.
180 degree
BeH2
Beryllium hydride.
Ionic and Covalent respectively
Cl3CF