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Yes, it is possible. There are two genetic alleles that together determine whether a person is Rh positive or negative. It is the combination of these alleles within the parents that determine the child's Rh status.
In this case, both mother and father are positive so their alleles can only be ++ or +-.
The possible combinations are determined by taking one allele from one parent and combining it with an allele of the other until all combinations are made. Positive is the dominant allele so combinations of ++ and +- are considered Rh positive whereas -- combinations are negative.
The possible combinations are:
++ which would be an Rh positive baby
+- which would be an Rh positive baby
-- which would be an Rh negative baby
So yes, it is possible.
Wiki User
∙ 11y ago
Wiki User
∙ 13y agoYes, it is even possible for both parents to be Rh+ and the baby to be Rh - although this would be more rare.
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no that isnt possible as the blood group will have to be the one in the childs parents.the membrane of the cell containsrhs which tell the type of bloob group.these rhs are transferred from the parents to the progeni.therefore the child is the bearer of the blood group of one or the other parent.
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#include<iostream> class base { int m_data; public: base(const int data):m_data(data){} base(const base& cpy):m_data(cpy.m_data){} base& operator=(const int rhs){m_data=rhs;return(*this);} base& operator=(const base& rhs){m_data=rhs.m_data;return(*this);} virtual ~base(){} }; class derived { public: derived(const int data):base(data){} derived(const derived& cpy):base(cpy){} derived& operator=(const int rhs){return(base::operator=(rhs));} derived& operator=(const derived& rhs){return(base::operator=(rhs));} virtual ~derived(){} }; int main() { derived d=42; }
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