Yes & No,
You are wanting the equation:
AB + C --> A + B + CA
Your equation is no longer balanced as you started with 1 A, and end with 2 A's.
Ok, let's try an example, and to try to make a balanced equation.
Water + ethene --> Hydrogen + Oxygen + ethane.
Now, I don't know if we could actually make the reaction work, but in theory it would be possible.
Let's now substitute in the symbols and try to balance the equation.
a(H2O) + b(C2H4) --> c(H2) + d(O2) + e(C2H6)
Ok, since we're conserving the carbons, let's set b=e=1
a(H2O) + C2H4 --> c(H2) + d(O2) + C2H6
In this case... if we let d=1, then a would have to equal 2, and we get:
2(H2O) + C2H4 --> H2 + O2 + C2H6
Count our Hydrogens, Carbons, and Oxygens:
4(H) + 2(O) + 2(C) + 4(H) --> 2(H) + 2(O) + 2(C) + 6(H)
and it all balances out.
Now, looking back at your original equation...
AB + C --> A + B + CA
Let A be Hydrogen Dimer (H2), or two hydrogen atoms,
B is Oxygen Dimer (O2), or two oxygen atoms,
C is Ethene. CA is Ethane (Ethene + 2 hydrogen atoms).
And you get:
A2B + C --> A + B + CA ... pretty close.
Again, this would probably require energy, and a little handwaving to make it all work, but one can get it to balance if one had initially started with 2 A atoms/molecules.
Ca(OH)2 + H2SO4 >> CaSO4 + 2H2O
double decomposition
Calcium=Ca=Atomic number 20 9+11=20
no , is the chemical formula by benda Benjamen
Ca2 is basically two Ca's so it's larger (the plus doesn't compensate)
No. Here is a proof by counterexample that it does not.Given ab + bc + ca = 3:Assume toward a contradiction that abc is a cube. Then a = b = c.Without loss of generality, let a = 2, b = 2, and c = 2.Then ab = 4, bc = 4, and ca = 4.ab + bc + ca = 4 + 4 + 4 = 12.Therefore, 12 = 3, which is false, and so the original statement is false.
Given that ab = ba and bc = cb We can arrive at abbc = cbba by adding equal quantities to both sides of the equation By the cancellation law you're allowed to drop the bb from both sides of the equation to end up with ac = ca
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2 Ca + 2O2 = 2(CaO2)
The aba-ca-by =2
Ca + Br2 = CaBr2 doesn't need to be balanced.
2Ca + 3O2 + 2C -> 2CaCO3
Exothermic (releases energy)
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
They do not react, the Calcium cannot displace the Potassium as it is less reactive.
It is already balanced
Ca(OH)2 + H2SO4 >> CaSO4 + 2H2O