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Can you declare a variable in different scopes with different data types elaborate with examples?
Wiki User
∙ 9y ago
Yes. Because a variable of the more local scope is what is used instead of any other variables with that name, the data types of the other variables that use that name are irrelevant.
It is, however bad practice to do this because it is confusing and often leads to unintentional function behaviour (particularly in weakly typed languages). If the variable in question is meant to be used in different functions and with a different purpose, there is probably no need to give it the same name as another.
Wiki User
∙ 14y ago
Wiki User
∙ 9y agoYes.
const int value {1}; // global value
void foo()
{ // new scope...
char value=2; // local variable (masks the global value)
value += (char) ::value; // use scope resolution to access the global value
{ // new scope...
double value=3.0; // local variable (masks the character value)
value += (double) ::value; // use scope resolution to access the global value
} // end of scope -- makes the character value visible
} // end of scope -- makes the global value visible
Note that it is not possible to access the local character value when the name is masked by another local (the double value). There is no scope resolution within nested scopes.
Of course, you would never deliberately write code such as this since it makes it that much harder to determine which instance of the value you are actually referring to. Using unique names makes it abundantly clear which value is being referred to.
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Can you declare a variable with abstract keyword?
no it is not possible
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Yes.
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no
Is it possible to declare a variable with abstract keyword?
yes
Why all variables are declared with in the function?
It is not necessary to to declare variables inside the function in C. If you declare a variable inside a function, the variable becomes local for the function and another variable of same name can be declared in any other function, but you can not use the variable declared in other function. When you declare any variable outside the function body then the variable becomes global and can be used in any function of the program. Note: errno is an example for a variable declared outside any function.
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variable exit within a function and curly braces is local variable int main() { int x; }
Can you declare any variable above preprocessor directive?
Yes.
