You mean you have written a program, but you don't understand it? Well, how could I explain it without seeing it?
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
class Fibonacci { public static void main(String args[]) { System.out.println("enter the number upto u want"); int number=Integer.parseInt(args[0]); int a=0,b=1,c=0; System.out.print(a+" "+b); for(int i=1;i<=number;i++) { c=a+b; System.out.print(c+" "); a=b; b=c; } } } the number are given to the run time where are print the series eg: 5 0 1 1 2 3 5 8 13................
Explain the following terms in the context of object oriented programming. Also explain how these concepts are implemented in C++ by giving an example program for each.
#include<stdio.h> int main(){ int a[10],i,n,m,c=0; printf("Enter the size of an array: "); scanf("%d",&n); printf("Enter the elements of the array: "); for(i=0;i<=n-1;i++){ scanf("%d",&a[i]); } printf("Enter the number to be search: "); scanf("%d",&m); for(i=0;i<=n-1;i++){ if(a[i]==m){ c=1; break; } } if(c==0) printf("The number is not in the list"); else printf("The number is found"); return 0; }
write a program to print the series 1/12+1/22+.........+1/n2 ?
Exactly what do you mean by 'C program in Java'
i dn't know. haha
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
Yes, this can be done. For example for Fibonacci series. You will find plenty of examples if you google for the types of series you need to be generated.
#include #include void main() { clrscr() int a=0,b=1,c,i,n; coutn cout
/*WAP to display Fibonacci series*/ #include<stdio.h> #include<conio.h> void main() { int i,a=0,b=1,c; scanf("%d",&n); printf("%d\n%d",a,b); for(i=0;i<n;i++) { c=a+b; a=b; b=c; printf("\n%d",c); } getch(); }
[ Fibonacci series___: ] #include<stdio.h> int main(void) { int n,i,c,a=0,b=1; printf("Enter Fibonacci series of nth term : "); scanf("%d",&n); printf("%d %d ",a,b); for(i=0;i<=(n-3);i++) { c=a+b; a=b; b=c; printf("%d ",c); } }
to print the Fibonacci series until 100 you can take the input in d to make it run for whatever value you want void main(){ int a,b,c,d; a=0; b=1; c=1; d=100; while(c<d) { printf("%d\n",c); c=a+b; a=b; b=c; } }
see the program
#include<stdio.h> #include<conio.h> void main() { printf("The first 20numbers of Fibonacci series are:"); int a=0, b=1, c, n=2; printf("%d \t, %d", &a, &b); while(n<20) { c=a+b; printf("\t %d", &c); a=b; b=c; n++; } getch(); }
find the program in c-pgms.blogspot.com
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }