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the simplest solution is by connecting two 120v 3amps heater in series , the same can be used directly on 240v. However the current drawn will still be 3 amps & Not 1.5 amps. The heater output power will be double that of a single heater running on 120v. ( or equvalent to two heaters operating on 120v. supply ) A more expensive method is to use a stepdown transformer which can be powered on 240v & connect the heater on the transformer 120v side. this method will consume approx. 1.5 amps from the 240v supply.
No. The neon sign is fed by a step-up transformer. Primary side 120V, secondary side 7500V. If you applied 240 to the primary side you would get 15000 volts on the neon tube. A flash over and then nothing. If you can find a transformer from 120V to 240V or 240V to 120V then you are good to go. Connect 240V to 240V side and you will get 120V out the other, connect the 120V side to the neon sign and you should have light. Transformer should be at least 100va. This will give you an output of .83 amps at 120V
You can energise the circuit by connecting to a neighbour's supply, then they will pay for the energy used. Anything different is classed as theft. An electrician would be needed to do the job safely.
120v
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You can find a 120V power cable at your local hardware store. Look in the section under extension cords.
no 208v is bigger
No.
12
It is 120V/60Hz
I think I understand what you are asking. 3-phase motors usually are equipped with a starter or contactor, since all 3 hot wires need to be switched. The control voltage that runs the starters is 120V, because it's safer and also 120V switches and relays are cheaper. You would have a 480-120V transformer (called a control transformer) in the starter box to provide the 120V "control voltage". So the arrangement you describe would have two contactors, with two phases reversed between them. Energize one, and the motor runs forward. Energize the other, and it runs reverse. The switch sends 120V to each of the contactors, which are equipped with 120V coils.