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No, you can not charge a 3V battery with 12V charger.

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Q: Can you recharge a 3V battery with 12V charger?
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How do you wire 6 batteries together to make 9 volts?

It depends on what you want to do with the batteries. They can be connected in series to give you a total of 12 VDC. In a series connection a jumper is required between battery one's negative post to battery number two's positive post. If you want to increase the amp hours delivered at 6VDC they can be connected in parallel. In a parallel connection two jumpers are required. Battery one's negative post to battery two's negative post. Likewise the same procedure with the positive posts.


If three lamps are connected in series to a 6 volt battery how many volts are impressed across each lamp?

In a parallel circuit, Voltage is constant through out the circuit. Thus, the voltage across each lamp is 6-volts.


What is the difference between a 1500 mAh and a 2800 mAh phone battery?

One lasts longer than the otherShort answer: a 2850 mAh will last quite a bit longer than an 1850 mAh. Long answer: mAh stads for "Milliamp hours" Many flashlight bulbs use around 500 mAh, which means that in one hour, they will use up 500 milliamps of electricity. A standard double A battery ("AA") is 1.5 volts. Many flashlight bulbs require 2 batteries to operate... So lets make an example bulb. It's a 3 V 500 mAh bulb. With two 2850 mAh AA batteries, that bulb will shine roughly 11.4 hours before needing a charge (2850 mAh times 2 batteries is 5700 mAh total. Divide that by the bulbs' 500 mAh and you get 11.4 hours) With a couple of 1850 mAh, the same bulb would only shine for 7.4 hours. As a battery gets close to dying the bulb will dim. Picture the battery like your lungs. Take a full breath, the battery is charged. Breath out at a constant rate, and when you get close to the end of your lung capacity you will start to push less and less air until you are just *barely* blowing any air out. That's kindof what happens with a low battery (EE's will probably blast me on that one, but that's the best way to describe it to someone who doesn't feel like reading a term paper on electrons)Hope that helps!--------------------------------Actually, if you put two 1.5V 2850mAh batteries in SERIES, you will get a 3V and 2850mAh battery. The voltage doubles but the current capacity does not. If you were to put the two batteries in PARALLEL, the voltage would remain 1.5V but the current capacity would double to 5700mAh. The consequence is that the bulb will shine half the time that was calculated in the original answer. The rest of the demonstration is fine.--------------------------------Some corrections the original answer:Firstly a typical rechargeable AA cell is rated at 1.2v not 1.5v. Non-rechargeable AA cells are typically 1.5v.Secondly mAh is a measure of the battery's capacity; bulbs do not have a capacity, so you do not rate a bulb in mAh you rate it in mA. So a conventional filament bulb as implied above might draw 500 mA from the cells when you apply 2.4 volts (in series).Some correction are in order assume 500mah means that battery can provide 500ma for 1 hour that is true. That the way should be read.. At 1 hour do not expect nothing more. And adding two battery in parallel is a very bad idea there can be circulating current between batteries adding in series the current remain 500mah but the power has increase two fold because now there is 2.4v available.


What hopes to the pressure of a gas if the volume of gas is tripled at a constant temperature?

PV=nRT If n,R,T are constant than the only thing that can change is P 3*V has to be cancelled out 1/3 * 3 = 1 1/3P * 3V = nRT


Can you use a 3.7v AC adapter for an LED light that recommends a 4V adapter?

You will be undervolting the LED by .3V, but otherwise it should work ok. Note the LED will not be quite as bright as it would be with 4V, but 0.3V isn't much to worry about. Also, make sure the adapter has the current capacity for the LEDs. If the LED draws more current than the supply can put out, it will not work and may burn up the adapter.