Chromium II phosphate is Cr3(PO4)2
Chromium (IV) oxide is CrO2
Cr2+
Cr(OH)3
CrO3
Chromium oxide may refer to:Chromium(II) oxide, CrOChromium(III) oxide, Cr2O3Chromium dioxide (chromium(IV) oxide), CrO2Chromium trioxide (chromium(VI) oxide), CrO3
Nitrogen(IV) oxide is N2O4.
PbO2
Balance the oxidation states on the atoms in the molecule. An oxide always contains oxygen in -2 oxidation state , in ionic compounds this is O2-. As the chromium is Cr(IV) in +4 oxidation state, ( shown as an ion Cr4+ ) you can balance the states or charges which ever way to get CrO2 (which you can write as Cr4+ (O2-)2 )
The Answer To Your Question Is.... tin (IV) oxide
Chromium oxide may refer to:Chromium(II) oxide, CrOChromium(III) oxide, Cr2O3Chromium dioxide (chromium(IV) oxide), CrO2Chromium trioxide (chromium(VI) oxide), CrO3
Chromium (II) chloride = CrCl2Chromium (III) chloride = CrCl3 Chromium (IV) chloride = CrCl4
The chemical formula for tin(IV) oxide is SnO2. Tin(III) oxide doesn't exist.
The chemical formula for tin(IV) oxide is SnO2. Tin(III) oxide doesn't exist.
Nitrogen(IV) oxide is N2O4.
That would be chromium(IV) selenide with the formula CrSe2
PbO2
Lead(IV) oxide would have the formula PbO2
Nitrogen dioxide NO2 Nitrogen(IV) oxide
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
SO2
Nitrogen(IV) oxide is N2O4.