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The phenotypic ratio will be 1:3.his son will be color blind.

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Q: Color blindness is an X-linked recessive trait A color-blind man has a daughter with normal color vision She mates with a male who has normal color vision What is the expected phenotypic ratio of t?
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Man who is color blind marries a woman not colorblind and doesn't have recessive allele will their children be carriers of the color blind allele?

50%AnswerColourblindness is a sex-linked recessive mutation i.e. the mutation is carried on the X chromosome. If a colour blind man married a carrier woman they could produce a carrier daughter, a colour blind daughter, a normal son or a colour blind son. The probability of each phenotype occurring is 25%.If XC represents the normal allele for seeing colour and Xc represents the colour blind allele the genotypes of the possible offspring would be as follows:Carrier daughter = XCXcColour blind daughter = XcXcNormal son = XCYColour blind son = XcYThis information is incorrect. In fact a woman can be color blind. My mother is color blind as are my brothers. My sister and I are not though we carry the gene. I have two daughters and one is color blind and the other is not color blind.The information I gave is not incorrect - I have included the possibility of that 'mating' producing a colour blind female child.


Is color blindness a sex linked disease?

Yes. A person is color blind if all his or her X chromosomes have the defective gene. A man have one X chromosome, and a woman has two. Thus: If only the father is color blind - The probability that the son is color blind is 0% - The probability that the daughter is color blind is 0% - The probability that the daughter is a bearer of the defective gene is 100% If the mother is a bearer of the defective gene, but is not color blind, and the father is not color blind - The probability that the son is color blind is 50% - The probability that the daughter is color blind is 0% - The probability that the daughter is a bearer of the defective gene is 50% If the mother is a bearer of the defective gene but not color blind, and the father is color blind - The probability that the son is color blind is 50% - The probability that the daughter is color blind is 50% - The probability that the daughter is a bearer of the defective gene is 100% If the mother is color blind and the father is not - The probability that the son is color blind is 100% - The probability that the daughter is color blind is 0% - The probability that the daughter is a bearer of the defective gene is 100% If both parents are color blind - The probability that the child, regardless of gender, is color blind is 100%


Red-green color is inherited as a sex linked recessive trait If a color-blind woman marries a man with normal vision what would be the expectes phenotypes of their daughter?

Zero chance for any daughter (she needs an X from mom and an X from dad and if dad is normal, then the daughter will only receive the normal X from him. So even if she gets a colorblind X from mom, she will not be colorblind). 50% chance for sons. Dad only contributes an X to the son. But mom can give either a normal X or a colorblind X. So there's a 50% chance of him being colorblind.


How does linkage affect the inheritance of traits?

As in sex linkage?Well if a trait is sex linked then one gender may be more likely to have that trait than the other. For example, colour blindness is a trait that is linked to the X chromosome. So males are more likely to be colour blind than females because the colour blindness gene is recessive and males only have 1 X chromosome where as females have 2 X chromosomes. Though females may be carriers of the colour blindness chromosome, therefore potentially passing it on to their children (son or daughter).


What is the probability that a color-blind woman will have a color- blind son?

The colorblind woman can pass the allele to all her children including sons and daughters but the daugthers will only be carriers for the trait whereas the sons will produce the trait. In order for the daughter to express the trait they would need the allele not only from the mother but from the father also. I just took an exam on this and got it right.

Related questions

A women wo isn't colorblind but has an allele for color blindness reproduces with a man who has normal vision what is the chance that they'll have a colorblind daughter?

There is no chance for a colorblind daughter because the x-chromosome that comes from the male is normal and then it does not matter which x-chromosome comes from the female because colorblindness is a recessive gene, therefore there is no chance.


What is the probability that a colorblind woman and a man with normal vision will have a colorblind daughter?

It all will depend on what kind of (recessive or dominant) alleles are responsible for the colorblind characteristic and what kind of alleles do the parental genes have.


A mother has one allele for color blindness and one allele for nomal vision what is the probability that her gamete will have the allele for color blindness?

Color Blindness is x-linked recessive. Therefore, it could not be heterozygous; the daughter would not be colorblind, but rather have normal vision.


A womens father is colorblind She marries a colorblind man Will there son or daughter be colorblind?

Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.


If a color blind man has a color blind daughter then the mother has to be color blind as well?

The father has to be colorblind for the daughter to be colorblind because both X chromosomes must have the colorblindness gene in females because the colorblind gene is recessive. If only the mother is color deficient, then she merely passes on the gene to one of the X chromosomes in a female. If both the mother and father are both colorblind, then both X chromosomes in the female are effected and the female is colorblind. There are two scenarios in which a daughter may be born colorblind. 1. The father is colorblind and the mother is a carrier of the colorblind gene. The daughter will be either colorblind or a carrier of the colorblind gene. 2. The father and mother are both colorblind. If this is the case, then all of the children will be born colorblind.


What is the probability that a woman who is a carrier of the colorblind gene and a colorblind man will have a daughter who will be colorblind?

the colorblindness is usually not activited in a female body but is usually seen in male


Is colorblindness a disability?

Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.


If Couples that have normal vision what is the probability of them having a color blind daughter and color blind son?

It depends on a number of different factors. If colorblind is common in either family but the mother/father were lucky enough not to get it, then its a recessive gene. but if its not common in either family then its a very low chance the child will be color blind. Although, if there are numerous people on both sides of the family the probability is very high. It all depends on a lot of different factors. How dominant is the gene? How many relatives are colorblind? If there are any, and they have children, are they colorblind? The easiest way to figure out if the child will be colorblind is to have the kid and test it for colorblind-ness.


Can a mother give a sex-linked trait to her son and her daughter?

The short answer is yes! The allele responsible for a sex-linked trait is carried on the X chromosome which a mother passes on to both sons and daughters. However, since sons have only that one X chromosome (from the mother - the other is the Y from the father) then even a recessive trait will always show up in the son. It is unlikely to show up in the daughter since the daughter inherits a second X chromosome from the father and since most traits are recessive then the 'normal' allele on the paternal X chromosome will mask the recessive one inherited from the mother. This is why the vast majority of people in the population showing a sex-linked trait are males. However, if the daughter were to inherit the recesisive allele from the father (as well as the mother) then she would be homozygous and the trait would show up....


A male who has normal vision marries a female who is a carrier for colorblindness can they have a colorblind daughter?

Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.


What would the genotypes of parents have to be for them to have a color-blind daughter?

The daughter's father would have to have been colour blind, and the mother would need the inheritive gene from her father (the mother doesn't nessecarily need to show it, just have a colourblind father) in order for a female to end up actually colourblind. However, it's extremely rare.


Why are males more likely to inherit sex-linked traits?

Females have XX chromosomes and males have XY chromosomes. Sex-linked traits are almost always carried on the X chromosome. Males are more likely to inherit sex-linked traits because they have only one chromosome that can carry a trait. If a male gets a recessive sex-linked trait, they will always acquire it because they have no other chromosome that will dominant over the recessive. In contrast, females have two X chromosomes which carry sex-linked traits. If they receive a recessive sex-linked trait, they always have one other chromosome that could be dominant over the other. For example: B - regular vision trait b - color blindness If a female has a colorblind father (XbY) and a mother with regular vision (XBXB), she will have XBXb. Even though the recessive colorblind trait was passed onto her, she will still have regular vision because of her other chromosome. Thus, she will be a carrier for colorblindness. Say the daughter above had children with a man with regular vision (XBY). If they have a son, there is a 50% chance he will be colorblind because of his mother who is a carrier. If they had a daughter, no matter what, she would always have regular vision with 50% chance that she will be a carrier.