29 protons and 27 electrons.
29 protons and 27electrons are present in Cu2+ ion.
The chemical symbol is Cu2+.
+2 is the charge represented Cu2+
The electron configuration of Cu2+ is [Ar]3d94s0.
The atomic number of copper is 29. Thus, neutral copper would have 29 protons and 29 electrons. However, since we're dealing with Cu2+, we need to subtract 2 electrons from that number, leaving us with 27.
Hg will have 80 electrons.
29 protons and 27electrons are present in Cu2+ ion.
Cu2+ + I- --> Cu2I The compound created is Copper(I) Iodide
Cu(s) | Cu2+(aq) Au+(aq) | Au(s)
Copper two
The chemical symbol is Cu2+.
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V
The octet rule does not apply to transition metals.
The overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu is 76 V.
Cu2+ + O2- + H+ + Cl- = Cu2+ + 2 Cl- + H2O
+2 is the charge represented Cu2+
E2xoy4=cu8