The electron configuration of Cu2+ is [Ar]3d94s0.
The electron configuration of Cu+ is [Ar]3d104s0.
It is 1s22s22p63s23p64s03d10 .
There is 1 unpaired electron in Copper (Cu)
Fr is in the 1st period. It removes an electron to get noble gas configuration. Fr+ does not have valence electrons.Francium has 1 electron in its outermost energy level. It donates its outermost electron to stabilize its electron configuration. Francium(I) has no valence electrons.
Cu(I), cuprous, Cu+.
the condensed electron configuration for Lu is [Xe] 6s^2 4f^14 5d^1
1 electron in the s orbital
There is 1 unpaired electron in Copper (Cu)
Cu+3 reported formally in 2007. Cu 1 e's in 4S and 10 e's in 3D Cu+3 0 e's in 4S and 8 e's in 3D LFSE suggets the existence of Cu+3.
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 Rb+1 or Kr
what is the electron configuration for Cl 1-
Fr is in the 1st period. It removes an electron to get noble gas configuration. Fr+ does not have valence electrons.Francium has 1 electron in its outermost energy level. It donates its outermost electron to stabilize its electron configuration. Francium(I) has no valence electrons.
Fluorine's electron configuration is 1s2 2s2 2p5, and since fluoride is just fluorine with an extra electron, or F-1, its electron configuration is 1s2 2s2 2p6.
Cu(I), cuprous, Cu+.
the condensed electron configuration for Lu is [Xe] 6s^2 4f^14 5d^1
1 electron in the s orbital
The electron configuration of magnesium is 1s2 2s2 2p6 3s2. Mg+ has one less electron (electrons have negative charge, so a positive charge is a lack of electrons) so you remove one from the outermost orbital: 1s2 2s2 2p6 3s1, or simply [Ne] 3s1.
29. Cu 1 is an ion where the Cu atom has lost an electron. Therefore, it would have the normal 29 neutrons.
The atom always stays in maximum stability.. The orbital with full electrons , no electron or half electrons is maximum stable ... In the case of Cu the electron moves in 3d orbital because in that case the 3d orbital is going to be filled with maximum 10 electrons hence the 4s orbital is going to be filled with half number of electrons - 1 electron ..... So the last electron goes in the 3d orbital except going into 4s orbital..... therefore the electron configuration of Cu is [Ar]3d10 4s1 .....The reason is same for the atom of Silver.....