V is the batteries rated voltage. Ah is the amp-hour of the battery. This is a rating of how many amps it can supply for a given period of time. For example a 600 Ah battery with a 100 A load means that the battery should last 6 hours.
No. The potential DIFFERENCE of a battery (or, more accurately, a dry cell) is 1.5 V.
6 volts
Assuming you're referring to a simple incandescent bulb . . .When the bulb burns out, the filament is open, and it is electrically no longer there.The voltmeter is then across the battery, which is open circuited, i.e. without a load.The meter measures the open-circuit voltage of the battery, nominally 6 V.
V=IR R=V/I V=3V I=0.075A R=3/0.075 = 40 ohms
The unit for electric potential difference is the volt (V).
Only if the battery is rated at 11.66V. mAh / 1000 => Ah (4800 mAh = 4.8 Ah) Ah * V => Wh (4.8 Ah * 11.66 V = 55.97 Wh)
The first choice was the best: 3 x 12 v 12 Ah will give a 36 v 12 Ah battery. In series the same current goes through all the batteries so the Ah capacity does not change.
75d23l (12 v - 52 ah).....
12 v 65 ah/20 hr
The 2.4 v battery doesn't have as many volts so the phone has less battery time, so you need to charge it more often, than the 3.6 v battery. Hope I helped you!
That depends on the characteristics of the battery. The numbers you quote don't give enough information. 4 Ah is simply a measure of the battery's total energy storage (for rexample, 1 ampere during 4 hours, at the specified voltage), not of how fast it can be released.
3.5v You add the voltages when placed in series.
If you're using the same input voltage, as the battery charger was designed for, then a simple socket adapter will make absolutely no difference to it's function. On the other hand, using a different input voltage to that which the battery charger was designed for, will make a considerable difference to the output voltage and current. Hence a 120 V automotive battery charger, if plugged into a 220 V socket will deliver nearly 24 V to a battery instead of 12 V, although the current supplied will be half it's normal value.
No. The potential DIFFERENCE of a battery (or, more accurately, a dry cell) is 1.5 V.
The idea is to use Ohm's Law (V=IR). In this case, the relevant voltage is the 10.2 V across the lamp.
Energy = 4Ah x 3600 seconds x 12 volts = 172,800 Joules
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