27 g (or 1 mole) of al will have 6.023 x 1023 atoms
So, 86.1 g will have (86.1 x 6.023 x 1023) / 27 = 1.92 x 1024 atoms Al
To calculate the number of moles equivalent to 5.75x10^24 atoms of Al, you would first need to determine the molar mass of Al, which is approximately 26.98 g/mol. Then, you would use Avogadro's number (6.022x10^23 atoms/mol) to convert the number of atoms to moles. This would give you approximately 96.1 moles of Al.
To find the number of aluminum atoms in 30 grams, you first need to determine the number of moles of aluminum using its molar mass (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
3.85 atoms Al (1 mole atoms Al/6.022 X 10^23) = 6.39 X 10^-24 moles aluminum ( though 3.85 atoms seems unlikely )
I assume you mean grams of aluminum. 4.1 X 10 -5 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 9.2 X 1017 atoms of aluminum ------------------------------------------
To calculate the number of atoms in 16.2 grams of aluminum, you first need to determine the number of moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the number of aluminum atoms in 16.2 grams.
By definition, 1 mole of anything is 6.022 x 1023 particles of that thing. So, 1 mole of Al = 6.022 x 1023 atoms Al 7.5mol Al x (6.022 x 1023 atoms Al/1mol Al)=4.5165 x 1024 atoms Al
1 mole Al = 26.98g/mol (atomic weight in grams)1 mole Al = 6.022 X 1023 atoms AlConvert 2.78g Al to moles.2.78g Al x 1mol Al/26.98g = 0.103mol AlConvert moles Al to atoms Al.0.103mol Al x (6.022 x 1023atoms/mol) = 6.20 x 1022 atoms Al
Al(OH)₃, or aluminum hydroxide, consists of one aluminum atom (Al), three oxygen atoms (O), and three hydrogen atoms (H). Therefore, the total number of atoms in Al(OH)₃ is seven: 1 aluminum + 3 oxygen + 3 hydrogen = 7 atoms.
To calculate the number of aluminum atoms in 2.78g of aluminum, you first need to convert the mass to moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to determine the number of atoms. The calculation would be: (2.78g Al) / (26.98 g/mol) * (6.022 x 10^23 atoms/mol).
1 mole Al ( and everything else ) is 6.022 X 10^23 atoms,so.... 6 mole Al (6.022 X 10^23/1 mole Al) = 3.61 X 10^24 atoms aluminum
The formula Al(NO3)3 contains 7 atoms in total: 1 aluminum (Al) atom and 3 nitrate (NO3) groups, each composed of 1 nitrogen atom and 3 oxygen atoms.
To convert from moles to atoms, you need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Therefore, to convert from 4.25 moles of Al to atoms of Al, you would use an equivalence factor of 6.022 x 10^23 atoms/mol.