By definition, 1 mole of anything is 6.022 x 1023 particles of that thing.
So, 1 mole of Al = 6.022 x 1023 atoms Al
7.5mol Al x (6.022 x 1023 atoms Al/1mol Al)=4.5165 x 1024 atoms Al
Answer: 8.6 Mol. To Find this you need to set up your dimensional analysis as: (5.2x1024atoms)(1 mol/6.022x1023atoms)= 8.6 Mol. Your atoms cancel out, so finish working the math out and your left with moles of Aluminum.
1 mole Al = 26.98g/mol (atomic weight in grams)1 mole Al = 6.022 X 1023 atoms AlConvert 2.78g Al to moles.2.78g Al x 1mol Al/26.98g = 0.103mol AlConvert moles Al to atoms Al.0.103mol Al x (6.022 x 1023atoms/mol) = 6.20 x 1022 atoms Al
To calculate the number of atoms in 16.2 grams of aluminum, you first need to determine the number of moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the number of aluminum atoms in 16.2 grams.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
There are 4 oxygen atoms in one molecule of aluminum carbonate (Al2(CO3)3). To find the number of moles of aluminum carbonate in 47.6g, we divide by its molar mass, 233.99 g/mol. Then, multiply by 4 to find the number of oxygen atoms.
To calculate the number of aluminum atoms in 2.78g of aluminum, you first need to convert the mass to moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to determine the number of atoms. The calculation would be: (2.78g Al) / (26.98 g/mol) * (6.022 x 10^23 atoms/mol).
To calculate the number of aluminum atoms in 3.24g of aluminum, first find the molar mass of aluminum, which is 26.98 g/mol. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Divide 3.24g by the molar mass of aluminum and then multiply by Avogadro's number to find approximately 3.01 x 10^22 atoms of aluminum in 3.24g.
Aluminum sulfide is Al2S3, which has 3 sulfur atoms per formula unit. 1.10mol means 1.10(6.02x1023), which is 6.62x1023 formula units. Multiple that by 3 to get your sulfur atoms: 6.62x1023(3) = 1.99x1024 sulfur atoms.
The molar mass of aluminum is 26.98 g/mol. To find the number of atoms in 16.2 g of aluminum, first calculate moles (16.2 g / 26.98 g/mol), then use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms.
Answer: 8.6 Mol. To Find this you need to set up your dimensional analysis as: (5.2x1024atoms)(1 mol/6.022x1023atoms)= 8.6 Mol. Your atoms cancel out, so finish working the math out and your left with moles of Aluminum.
To find the number of aluminum atoms in 30 grams, you first need to determine the number of moles of aluminum using its molar mass (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
1 mole Al = 26.98g/mol (atomic weight in grams)1 mole Al = 6.022 X 1023 atoms AlConvert 2.78g Al to moles.2.78g Al x 1mol Al/26.98g = 0.103mol AlConvert moles Al to atoms Al.0.103mol Al x (6.022 x 1023atoms/mol) = 6.20 x 1022 atoms Al
To calculate the number of atoms in 16.2 grams of aluminum, you first need to determine the number of moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the number of aluminum atoms in 16.2 grams.
Mass of Aluminum Sulfate: 2.74g Molar Mass of Aluminum Sulfate: 342.14 g/mol Therefore, number of moles of Oxygen can be calculated by 2.74g * 12/342.14 g/mol = 0.096 moles Now since u have the moles of Oxygen, the number of oxygen atoms is given by 0.096 mol * (6.02*10^23) particles or atoms/mol that gives u about 5.78 * 10^22 atoms of oxygen
The number of aluminium atoms ia 0,44638973.10e23.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
There are 4 oxygen atoms in one molecule of aluminum carbonate (Al2(CO3)3). To find the number of moles of aluminum carbonate in 47.6g, we divide by its molar mass, 233.99 g/mol. Then, multiply by 4 to find the number of oxygen atoms.