Two pair works like this, the higher pair determines who is the winner. Suppose I have two pair Aces and fives, that means I beat all two pair that have kings as the higher pair, and queens etc. So Aces and fives beats Kings and queens. Now, if there is tie then the second pair comes in, so Aces and fives loses to Aces and sevens.
No, a full house beats two pair
In poker, yes.
The pair of queens beat the pair of tens, the nine and the ace are irrelevant. Queens are higher ranked than tens.
5/10 is greater
Three aces and two eights is a full house. Three Aces and two nines would win. As would three aces and two kickers 10 or higher.
Two pairs of aces (called 4 of a kind) does beat a flush.
It depends on the type of poker game being played.In a game where aces are low (they are equivalent to the number 1). In that case yes, a pair of fives beats a pair of aces.In a game where aces are high, then no, the pair of aces definitely wins. A pair of aces is the highest single pair you can get in the game of poker, before getting two pair or higher.Both of these types of games are played in poker.
yes
No.
The two pair, although lower, beat the pair of Aces.
Suit (club) does not matter unless you have a total of 5 same suited cards between your hand and the table. If you only have 2 clubs, you do not have a flush. Therefore, a pair of Aces does not beat a flush.