yes. the positive end of the molecule attracts the negative end of the adjacent molecule
A water molecule is polar, which is why it attracts other polar molecules.
Water molecules attract the opposite poles of other polar molecules through poles present in water itself.
Not much really except molecules should have polar bonds so that the bonds attract to other poles causing molecules to bond and form larger things. Its like how the electrons of atoms attract other atoms or collide and form molecules.
hydrophilic
adhesion
Water is a polar covalent molecule. The partial charges in the molecule attract other charges, ionic or more partial charges from other covalent molecules and dissolves them. Nonpolar bonded molecules have no partial charges and the water molecules will attract each other thus not attracting the nonpolar and does not dissolve them.
When soap is mixed with octane the non-polar ends of the soap molecules are attracted with induced-dipole induced-dipole attractions to the non-polar octane molecules. The octane molecules repel the polar ends of the soap and the soap molecules form inverted soap bubbles that attract polar molecules like water.
Yes, but they attract polar molecules more strongly."Hydrophobic" molecules is a misnomer. The nonpolar molecules in question are attracted to water molecules (usually more strongly than they're attracted to each other, even), but they get "shoved out of the way" by polar "hydrophilic" molecules which are even more strongly attracted to water molecules.
Water weighs more than gasoline because the particles in water are more dense than those in gasoline. This is because water molecules are highly polar and tend to attract each other. Gasoline molecules are not nearly as polar and do not attract each other.
Non-polar molecules are more attracted to other non-polar molecules.
Which of these molecules is polar
This is because of its polar nature - water molecules have a strong dipole, therefore, the water molecules attract each other more than most other molecules do.