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You have not provided enough information. For 12 volt peak to peak, purely AC signal, there will be no DC (hence purely AC). This means there is no offset - the AC signal peaks at 6 volts and -6 volts. The RMS value of this is VRMS = peak / sqrt(2) = 6 / 1.4.
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoYes and no. RMS is simply a way of measuring a value over time. You take a series of instantaneous measurements (snapshots), then calculate the square root of each one, average them, and square the result. Sure, you can do these calculations on a DC signal, but since the instantaneous value never changes with time, the output is the same as the input, in other words, the RMS value of 10 volts DC is 10 volts. For this reason, RMS calculations are never used for DC. There is no point.
Wiki User
∙ 15y agoThe RMS value is the effective value of an AC voltage. It is the equivalent steady DC (constant) value which gives the same effect (heat or light). For more, see link below:
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Which wave is highest RMS value peakvalue being the same?
The wave with the maximum RMS value, in comparision with the peak value, is the square wave.
The rms value of the resultant current in a wire which carries a DC of 20A and a sinusoidal ac of peak value 20A is?
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
The rms value of the resultant current in a wire which carries a DC of 10A and a sinusoidal ac of peak value 20A is?
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
Will value of J be same if ac were used instead of dc?
The number of Joules (energy) is the same as dc provided the RMS values of the ac quantities are used.
Household supply of 230volts is rms value or maximum value of voltage?
When you say holdhold supply of 230volts, you are referring to the RMS value, not the peak value.
How do you convert an RMS current value to a DC value?
RMS current is converted to DC current by using a rectifier. Capacitors and other components are used to make a cleaner DC output with less ripple.
How do you change dc values to ac values?
To convert DC values to AC values if you are wanting RMS values they are the same. 100V DC and 100V AC (RMS) are the same "value". If you want to know the Peak-To-Peak AC value you would multiply the RMS value by 1.414. So 100V AC RMS equals 141.4 V Peak to Peak.
Which wave is highest RMS value peakvalue being the same?
The wave with the maximum RMS value, in comparision with the peak value, is the square wave.
In roughness measureing system what is RMS value?
RMS value is defined as "The amount of ac supply required to make same heat effect in resistor , which is made by dc current, in that resistor"
The rms value of the resultant current in a wire which carries a DC of 20A and a sinusoidal ac of peak value 20A is?
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
AC or DC supply is given to a bulb which gives more illumination?
In AC supply, the RMS current is the effective current for power used in a resistive circuit. This is defined as the square root of the mean value of the square of the current, taken over a whole cycle. The RMS current dissipates power at the same rate as a DC current of the same value. A light bulb of course gives out light dependent on the current through the filament. So if the RMS current and the DC current are the same value, the light produced will be equal. With AC supply, the RMS value of current and volts is 1/(square root of 2) x the peak value, so peak value = 1.414 x RMS value. If you supplied DC at volts and current equal to the peak AC value, the power given to the light bulb would clearly be greater. Therefore to answer your question you have to specify what relative values your AC and DC supplies have.
How do you find the peak value of 110 volts RMS?
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
The rms value of the resultant current in a wire which carries a DC of 10A and a sinusoidal ac of peak value 20A is?
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
The rms voltage is obtained by multiplying peak by a factor?
Multiply the peak to neutral by .707 for a sine wave. The RMS value is the equivalent level available if it were DC, so it will always be lower than the peak value.
What is the peak voltage of a sine wave that measure 220V AC rms?
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.
Will value of J be same if ac were used instead of dc?
The number of Joules (energy) is the same as dc provided the RMS values of the ac quantities are used.
Volts peak is equals to dc volts?
"Voltage peak" is generally used to denote the maximum(amplitude) of AC voltage supply. It can not be approximated as dc value. The closest approximation one can make for dc value of a ac supply is the RMS(root mean square) value of the voltage. So that the ohmic loss caused by the given AC voltage supply is equivalent to that caused by a dc supply having value equal to the RMS of this AC supply (for given impedance & time).
