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An enantiomer is a pair of structures which are mirror images of each other. For D-glucose:CHO | CHO| | |H--OH | OH--H| | |OH--H | H--OH| | |H--OH | OH--H| | |H--OH | OH--H| | |CH2OH | CH2OHOn the left is D-glucose, and on the right is L-glucose, mirror images.
glucose molecule contains OH groups, which forms hydrogen bonds with OH of water molecules, therefore glucose is soluble in water. however in patrol is an hydrocarbon compounds, glucose is polar and patrol is non polar (so like dissolves only like), glucose in not soluble in patrol.
The structure of Galactose monosaccharide sugar is a normal chain of six carbon atoms. It is an isomer of Glucose and Fructose. Below is a structure of Galactose in open chain form:H-C=O|H-C-OH|OH-C-H|OH-C-H|H-C-OH|H-C-OH|OHTo understand the pyranose ring form of Galactose, draw a hexagon, assume the joints as carbon atoms except one joint- that is an oxygen atom.Let the joints be A, B, C, D, E, F. To the joints A, C, D, E, F, assume them to be carbon atoms, and the joint B to be oxygen atom. They are joined to each other by single bonds. Now attach -CH2OH group to carbon atom A vertically upwards and -H vertically downwards. Leave oxygen atom B as it is because its stabilised. To carbon atom C, attach -H vertically upwards and -OH group vertically downwards. Repeat this with carbon atom D; & reverse the positions of -H and -OH group in the carbon atoms E and F, as it is done in the open chain form. Actually, in very brief, you only have to show glycosidic-1,4 linkage in the open form of Galactose to express it in pyranose ring form.
Because glucose has many -OH groups, which are capable of forming hydrogen bonds with water molecules.
SUGAR-OH
Dissolve it in water. This causes the -OH group on one end to react with the C=O group on the other end to form an oxygen link to produce a six-carbon ring.
They form different disaccharides due to there molecular structures. Alpha forms Maltose with a 1-4 glycosidic bond between each alpha glucose and another, and Beta forms the disaccharide Cellobiose with a 1-4 glycosidic bond between each beta glucose and another.
An enantiomer is a pair of structures which are mirror images of each other. For D-glucose:CHO | CHO| | |H--OH | OH--H| | |OH--H | H--OH| | |H--OH | OH--H| | |H--OH | OH--H| | |CH2OH | CH2OHOn the left is D-glucose, and on the right is L-glucose, mirror images.
Glucose is sparingly soluble in ethanol. This is because the organic molecules of the ethanol are too large to separate the glucose, unlike water where the water molecules are easily able to dissolve the crystalline structure to react with the -OH groups.
glucose molecule contains OH groups, which forms hydrogen bonds with OH of water molecules, therefore glucose is soluble in water. however in patrol is an hydrocarbon compounds, glucose is polar and patrol is non polar (so like dissolves only like), glucose in not soluble in patrol.
-OH
glucose has less solubility than sodium chloride because of the more OH bonds
The structure of Galactose monosaccharide sugar is a normal chain of six carbon atoms. It is an isomer of Glucose and Fructose. Below is a structure of Galactose in open chain form:H-C=O|H-C-OH|OH-C-H|OH-C-H|H-C-OH|H-C-OH|OHTo understand the pyranose ring form of Galactose, draw a hexagon, assume the joints as carbon atoms except one joint- that is an oxygen atom.Let the joints be A, B, C, D, E, F. To the joints A, C, D, E, F, assume them to be carbon atoms, and the joint B to be oxygen atom. They are joined to each other by single bonds. Now attach -CH2OH group to carbon atom A vertically upwards and -H vertically downwards. Leave oxygen atom B as it is because its stabilised. To carbon atom C, attach -H vertically upwards and -OH group vertically downwards. Repeat this with carbon atom D; & reverse the positions of -H and -OH group in the carbon atoms E and F, as it is done in the open chain form. Actually, in very brief, you only have to show glycosidic-1,4 linkage in the open form of Galactose to express it in pyranose ring form.
Monosaccharides are building blocks of carbohydrates. They can exist in chain form or ring form, and in many cases, the only difference in these structures is in the arrangement of the hydroxyl groups.
Because glucose has many -OH groups, which are capable of forming hydrogen bonds with water molecules.
OH | / \
Sugar means Kitchen sugar used to sweeten ediables. Sugar is made of 2 molecules of Glucose and Fructose one each. If you see chemical structure of glucose it has more -OH radicals then others. -COOH is stands for carbonic acid.