Yes - it takes longer to freeze water if you add heat - or melts it, if already frozen
The shape of a container affects the freezing rate of water because it can impact the surface area exposed to the surrounding environment. A container with a larger surface area allows for more heat transfer, resulting in faster freezing. Conversely, a container with a smaller surface area will have slower heat transfer and slower freezing.
The amount of water in a container will affect how fast it heats up. If there is a small amount of water in a container the water will biol/heat faster. However, if there is a big amount of water it will take longer for the heat to reach all parts of the water resulting in a longer time for the water to boil/heat
Freezing ice is a process that involves heat loss. When liquid water turns into ice, heat escapes from the water, causing it to lose energy and lower in temperature.
Salt decreases the freezing point of water and increases the boiling point of water.
Heat tape is just for keeping the pipes from freezing, it does not heat the water. That's what the hot water heater is for.
heat it up, add energy to it
At 0 degrees Celsius, whether water is melting or freezing depends on the direction of energy flow. Melting occurs when heat is added, while freezing occurs when heat is removed. If water is at exactly 0 degrees Celsius, adding heat will cause it to melt into liquid water, and removing heat will cause it to freeze into ice.
Yes because it is no longer water so will have a different freezing time or point
It doesn't.
no
Yes, the amount of water can affect how fast it freezes. A larger volume of water will take longer to freeze compared to a smaller volume because there is more heat energy that needs to be removed to lower the temperature of the water to the freezing point.
The amount of energy generated from freezing 2.5g of water can be calculated using the specific heat capacity of water and the heat of fusion for water. The energy released would be equal to the heat of fusion of water (334 J/g) multiplied by the mass of water (2.5g). By multiplying these values, you can determine the total energy released during the freezing process.