Yes, such a hypothetical drive would probably be able to do that. That means it isn't possible to build one.
The surface area of mitochondria or chloroplast affect its energy output because larger surfaces-to-volume ratio imply more loss of energy as opposed to smaller surface-to-volume ratios.
as upto 3db only the amplifier gives the linear output & after that it gives non linear so it is difficult to determine it's characteristics.also up to 3 db it's energy efficiency is 70.3%. ANSWER: It imply that the amplitude on the output is half.....................
8bit 16 bits 32 bits and 64 bits and 128 bits imply a broadside [parallel] output of that many bits of digital information on a buss output. these bits represent a word output. therefore the longest the word the more information can be processed at a time imply more bits the faster the computer or data flow.
A: Voltage follower imply that the output will follow the input without any gain.
Yes, it is a chemical reaction because imply the partial thermal decomposition of sugar.
Catalyst active sites are specific regions on a catalyst where reactants bind and undergo a chemical reaction, facilitating the conversion of substrates into products without being consumed in the process. These sites enhance the reaction rate by lowering the activation energy required for the reaction to occur. In contrast, "subtract" generally refers to the act of taking away or removing something. In the context of chemistry, it may imply the removal of reactants or products from a reaction system, impacting the overall reaction equilibrium.
E=mc^2 states that mass and energy are interchangeable, and that a little bit of mass creates a lot of energy.
energy can neither be created nor we destroy That energy can only be converted between different forms ~Apex
A low k value, often referring to the rate constant in chemical kinetics or the equilibrium constant in thermodynamics, indicates a slower reaction rate or a lesser tendency for products to form compared to reactants. In the context of a reaction, it suggests that the equilibrium favors the reactants, meaning that the reaction does not proceed significantly toward the formation of products. This can imply a more stable state for the reactants or a higher activation energy barrier for the reaction to occur.
A lysis, though this term if prefered for cells destruction. For a molecule, you precise the kind of reaction : if the reaction imply water, it's an hydrolysis (for macromolecules, it usually is), but other kinds exists like hydrogenolysis.
No, an efficiency greater than one would not be possible, since that would violate a very fundamental law of physics: conservation of energy. The efficiency of an "ideal machine" would be one, in many cases; the efficiency of an ideal Carnot engine would be less than one.
A steep increase in the slope of a line on an Ellingham diagram indicates that the reaction becomes increasingly more favorable at higher temperatures. This typically suggests that the Gibbs free energy change (ΔG) for the reaction decreases significantly with an increase in temperature, making the formation of the compound more thermodynamically favorable. It can also imply a stronger dependence of the reaction on entropy changes at elevated temperatures.