It depends.
If the child is male, the person to pass the trait on must be the mother. She may be a hybrid or color-blind herself for her to be capable of doing this. If the child is female, the father must be color-blind in addition to the mother being a carrier. Both have to donate the recessive gene to their daughter.
The father passes this gene on the son's and daughters.
his mother because color blindness is a sex-linked trait that is found on the X chromosome, which is inherited from the mother, as opposed to the Y chromosome, which is inherited from the father. So a male can only inherit the gene for color blindness from his mom.
X' = color blindnessX'X'-- X --X'Yis a cross that could lead to a color blind female as the mother is homozygous recessive and the father's X chromosome is the recessive color blind trait.
All daughters are normal, half the sons are color blind. The above answer is incorrect. Half of the daughters are color blind and half of the sons are color blind. Since the father always donates color blindness, it is up to the mother in each case (in the son's case, the father is irrelevant) to determine if the child is color blind or not. Since she is a carrier, the chance is 50-50.
Women can be colour blind.AnswerI am a woman who is red--green colorblind. The trait is carried on the X chromosome. Males receive an X chromosome from their mother and a Y from their father. If the X carries the trait of colorblindness, the male will be colorblind. Females need to receive two defective X chromosomes to be colorblind, one from their father and one from their mother. If a women has only one defective X chromosome, she will be a carrier of the trait. My father was red-green colorblind and so was my mother's father, making my mother a carrier of the trait, although she is not colorblind herself. I have two sisters who are not colorblind, as they each received a non-defective X chromosome from my mother. I knew before my son was born that he would be red-green colorblind, as the X chromosome he received from me carried the trait.
BLhah
She has at least one recessive color blindness allele {apex}
The father has to be colorblind for the daughter to be colorblind because both X chromosomes must have the colorblindness gene in females because the colorblind gene is recessive. If only the mother is color deficient, then she merely passes on the gene to one of the X chromosomes in a female. If both the mother and father are both colorblind, then both X chromosomes in the female are effected and the female is colorblind. There are two scenarios in which a daughter may be born colorblind. 1. The father is colorblind and the mother is a carrier of the colorblind gene. The daughter will be either colorblind or a carrier of the colorblind gene. 2. The father and mother are both colorblind. If this is the case, then all of the children will be born colorblind.
Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman is a carrier, Xx, and a man is normal, XY, they have several different chances for different offspring: XX (a normal girl) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) xY (a colorblind boy) The short answer is, that if a woman has a boy, he has a 50% chance of being colorblind.
The daughter's father would have to have been colour blind, and the mother would need the inheritive gene from her father (the mother doesn't nessecarily need to show it, just have a colourblind father) in order for a female to end up actually colourblind. However, it's extremely rare.
His mate is color-blind
The Blind Kind
The most common type of color blindness is a sex-linked trait, meaning the gene is carried on the chromosomes that determine sex. In this case, it's carried on the X chromosome. There are other types of color blindness that are inherited that are not sex-linked, so it doesn't matter which parent is the carrier. Males are XY, and therefore can pass either an X or Y to their offspring, making them the actual determinants of the sex of the offspring. Females are XX, and so can only contribute an X. In the case of color blindness, since males only get one X, if that has the gene for color blindness on it, the male will be color blind (in this case, we'll call that one "x" rather than "X". In the case of females, she has two - so if only ONE of her X has the gene, she will be a carrier, but will not have it (Xx). If her father is colorblind (xY), and her mother is a carrier (Xx), she has a 50% chance of being colorblind (she'll either be "xx" or "Xx). If her mother IS colorblind (xx) and her father is too (xY), then there is only one outcome: "xx". So, if a color blind mother (xx) has children with a non color blind father (XY), there are the possibilities: xX, xY. Her daughters will be carriers, and her sons will be color blind. If a color blind mother (xx) has children with a color blind father (xY), then these are the possibilities: xx, xY. All children will be color blind. To sum up, a mother with sex-linked colorblindness will always have color blind sons, and daughters will have a 50% chance of being color blind, depending on if the father is or not.