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Kinetic energy is equal to the mass of the object times the velocity squared (Ek=.5mv2). To obtain the ratio between the two objects, divide the first by the second (Ek1/Ek2). This is equivalent to .5m1v12/.5m2v22. Since the masses are equal, they cancel out and you are left with v12/v22. Next, as stated in the problem, the seceond velocity is twice as much as the first so plug that coefficient into the aforementioned equation. (1v12)/(2v22). Since the values of velocity (v) are equal in this problem, they can cancel out just as the masses did. Now, 12=1 and 22=4; so the ratio is 1/4.
Efficiency is equal to the ratio of work input to work output; for an ideal machine this ratio is equal to 1 or 100%. For a real machine this ratio is always less than 1 because some of the work input is used to overcome mechanical friction within the machine which does not contribute to the work output of the machine.
GIven m1v1 = m2 v2 -----------------(1) Needed m1v12 / m2v22 = v1 / v2 But right from (1) v1 / v2 = m2 / m1 Given m1 = 1 g and m2 = 4 g So required ratio of KE = 4:1
Areas
-- Measure the weight of the marble. -- While on the same planet, measure the weight of the basketball. Since both measurements were made on the same planet, the ratio of the weights is the same as the ratio of the masses. -- Divide the big weight by the small weight (Wb/Wm); call the answer ' R '. -- Start the basketball moving, and measure its speed; call the speed ' S '. -- Make the marble move at a speed of ( R times S ). Their momenta are now equal. Momentum = (mass) times (speed), and that product is now the same for both objects.
Kinetic energy is equal to the mass of the object times the velocity squared (Ek=.5mv2). To obtain the ratio between the two objects, divide the first by the second (Ek1/Ek2). This is equivalent to .5m1v12/.5m2v22. Since the masses are equal, they cancel out and you are left with v12/v22. Next, as stated in the problem, the seceond velocity is twice as much as the first so plug that coefficient into the aforementioned equation. (1v12)/(2v22). Since the values of velocity (v) are equal in this problem, they can cancel out just as the masses did. Now, 12=1 and 22=4; so the ratio is 1/4.
No it is not equal to a ratio.
The fixed ratio of the elements in a chemical compound is called its RATIO OF MASSES.
The ratio is the same. Inertia depends entirely on mass.
Which ratio is equal to 54 : 24?
salt and water
The chemical formula of the compound shows the ratio of the atoms of elements in a compound. This must not be confused with the ratio of their masses.
yes the ratio 2 to 5 is equal to 5 to 2 * * * * * No, they are not equal. That is like saying that two is equal to a half!
an eqivalent ratio is an ratio that is equal or you can simplfiy it
15:24 is not equal to the ratio 15 to 25.
No.
The ratio 3 to 2 is equal to 1.5.