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What is the apparent weight for a body floating in water equal to?
The apparent weight of a body floating in water is equal to the weight of the water displaced by the body. This is known as Archimedes' principle. The apparent weight is less than the actual weight of the body due to the buoyant force acting on it.
What happenning if the weight of the body equal to zero in the water?
If the weight of a body in water is zero, it means the body is in a state of neutral buoyancy where it neither sinks nor floats. This occurs when the weight of the water displaced by the body is equal to the weight of the body itself.
What is the relation do you find between the weight of the floating body and the weight of water that is displaced?
The weight of the floating body is equal to the weight of the water that is displaced. This relationship is known as Archimedes' principle. The buoyant force acting on the floating body is equal to the weight of the water it displaces, allowing the body to float.
What percent of a human weight is made of water?
Almost 60 % of body weight is composed of water. 40 % of the body water is in the intracellular compartment and 20 % of the body water is there in extracellular compartment.
The volume of the displaced water is equal to the volume of the portion of the object that's above the surface of the water?
This statement is not correct. The weight of the water displaced by a body in it, is equal to the buoyancy force that the body will experience. In the case the body floats on the surface of water, the weight of the water displaced by the body is equal to the weight of the body.
If a body is immersed in water will the weight of the body increase?
No, the weight of the body will not increase when immersed in water. The weight of an object is determined by the force of gravity acting on it, which remains constant regardless of whether the object is in water or in air. The apparent weight of the body will be less in water due to the buoyant force acting on it.
How is the weight of water displaced by a floating body related to the weight of the body itself?
The weight of water displaced by a floating body is equal to the weight of the body itself. This is known as Archimedes' principle, which states that the buoyant force acting on a body immersed in fluid is equal to the weight of the fluid displaced by the body.
Why and how does a body lose weight when it is immersed in water?
When a body is immersed in water, it experiences buoyant force which reduces its weight. This results in a decrease in apparent weight, which can be misinterpreted as weight loss. However, the actual mass of the body remains the same as the buoyant force only affects the apparent weight.
Why does a spring balance show less weight of a body when the body is immersed in water?
Spring balance shows remarkably less weight of yours, when immersed in the water. Your weight will be shown less as much the weight of water you have displaced.
A body weighs 100N in air and 65N when submerjed in water calculate the upthrust on the body?
The weight of the body in water is reduced by the weight of the water displaced, which is 100N - 65N = 35N. Therefore, the upthrust on the body is 35N.
How much of a man's body is water?
Water accounts for about 60% of a man's body weight.
What is happening if the weight of the body in the water becomes zero?
If the weight of a body in water becomes zero, it means that the buoyant force acting on the body is equal to the weight of the body. This implies that the body is completely submerged and in equilibrium, neither sinking nor rising.
