I measure the efficiency of an internal combustian engine by doing
(bhp)/((displacement)*(rpm))
80%
EFF1 is a high efficiency motor. EFF2 is a standard efficiency motor.
Yes this is what we call efficiency of the motor. We give 100 but the motor in turn gives 40, so its efficiency is 40%
Motor size depends upon number of factore. 1- flow of pupm 2- required head 3- efficiency of pupm used 4- efficiency of electric motor used The formula is H.P required= Q.H\ 3960. Pump efficiency. Motor efficiency where Q= GPM H= Ft Efficiency= In fraction( 70 % = 0.7) Engr. Usman Khalid +923336901945 usman.engr87@gmail.com
It is maximum at about 75% to 100% of the motor rated load. Efficiency is maximum at unity power factor , when R=X and when variable losses Is equal to constant losses at rated load.
Motor efficiency depends on the motor size and how much it is loaded. You get the best efficiency above 75% of the rated load for that motor. Note the table below: Horsepower Standard Premium Efficiency Efficiency% Efficiency% 1 --- 78.0 --- 82.5 2 --- 78.5 --- 84.0 5 --- 84.0 --- 89.6 10 --- 84.0 --- 91.1 15 --- 87.5 --- 91.7 25 --- 90.2 --- 93.0 50 --- 91.7 --- 94.1 100 --- 91.7 --- 95.0 250 --- 94.1 --- 95.8
You can calculate the quantity of energy that a motor turns into heat with either one of these equations: Heat energy = ( 1 - efficiency of the motor) x (energy input to the motor) or Heat energy = ( 1 - efficiency of the motor) x (power input to the motor) x (running time)
ratio of energy output to energy input.
The efficiency of a motor is the output power divided by the input power. The difference is the lost power which appears as heat usually. High-efficiency motors produce very little lost power. But they tend to be more massive and expensive to make, so that most motor designs have to compromise on efficiency.
For a motor's output power to equal its input power, the motor's efficiency must be 100%. As no machine, particularly a rotating machine, can possibly achieve 100% efficiency, there is no condition under which its output power can ever match its input power.
such a motor would be theoretically 82.8888% efficient
i think both will be same..