You can check it out yourself using these formulas. Watts = Amps x Volts. Voltage = Watts/Amps
It depends on the voltage rating.
What is the voltage and current of an integrated cicuit
yes
A zener diode with a rating of 500 mW will pass 50 mA at 10 V. (Power = voltage times current)Note: The question appears mis stated, in that it states a rating of 500 MW, not 500 mW. To my knowledge, there is no zener with a rating of 500 MW.
the High voltage rated diodes are power diodes while of low rating or normal voltage rating are considered to as ordinary / normal diode
It depends on the voltage rating.
What is the voltage and current of an integrated cicuit
Wattage or power rating of a product can be calculated by multiplying voltage rating and current rating. (Power = Voltage x Current). e.g. if device is working at 12V and 2A is the current rating. It is 24Watt. Since Voltage = Current x Resistance , for a resistive load power can also be calculated by Power = Current x Current x Resistance = I^2 x R = I square R
True power is expressed in watts, so the true power of your heater is its kilowatt rating at its rated voltage. Variations in voltage will result in variations in its power. Assuming its resistance remains roughly constant for variations in temperature, then True Power = V2/R.
350
yes
A zener diode with a rating of 500 mW will pass 50 mA at 10 V. (Power = voltage times current)Note: The question appears mis stated, in that it states a rating of 500 MW, not 500 mW. To my knowledge, there is no zener with a rating of 500 MW.
the High voltage rated diodes are power diodes while of low rating or normal voltage rating are considered to as ordinary / normal diode
This is dependent on what you're looking for in voltage and power rating. Small IC's can be purchased for ~$1.00.
Welding is done with a high current and low voltage. The voltage of a 500 amp welder might be 10 v so the power rating in that case would be 5000 watts.
Ratio of voltage rating and current rating is called power factor in electricalAnswerPower factor can be defined in a number of ways -for example:cosine of the phase angleratio of true power to apparent powerIt has nothing to do with the ratio of voltage rating to current rating!
It depends on the voltage applied across it. But the maximum current is limited by the power-rating of the resistor (power divided by the square of the voltage).