x18 - 1 = (x9 - 1)(x9 + 1). This is a special case of the formula n2 - 1 = (n -1)(n + 1).
18x2 is one term. You need at least two terms to find something in common.
x(x + 1)(x - 1)
18th December
This is 220 volts AC, I assume. 10 x 220 = 2.2kVA of power. The real power will depend on the power factor. Take the power factor times 2,200 to find the watts.
(x+1)(x-1)
(x - 1)(x + 1)(x2 + 1)
36
x(x + 1)(x - 1)
(x + 1)(x^2 - x + 1)
x(x - 1)
In an AC system power is equal to Voltage x Current x Power factor. Power factor is not constant and depends on the type of the load. Ideal value of the Power factor is 1, where as practically remains less then 1.
its equal to 1 Amps 6.25 x 10 to the 18th power
Power = volts x amperes x power factor. However, VA or kVA is simply the product of volts x amperes, and does not take into account the power factor. Note that in many practical situations, the power factor is close to 1.
(x + 1)(x - 1)
(x2 - x + 1)(x2 + x + 1)
(x - 1)(x^2 + x + 1)
18th December
In DC, power equals voltage x current. In AC, power equals voltage x current x power factor. The power factor is an adimensional constant, and in common circuits it is often close to 1.