+6
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
The oxidation number of sulfur (S) in CaSO4 (calcium sulfate) is +6. This is because calcium (Ca) has an oxidation number of +2 and oxygen (O) almost always has an oxidation number of -2. Therefore, the sum of the oxidation numbers must equal zero for the compound CaSO4.
The oxidation number for Sulfur (S) in CaSO3 is +4. This is because Calcium (Ca) has an oxidation number of +2 and Oxygen always has an oxidation number of -2. By setting up the equation Ca(+2) + S(x) + 3O(-2) = 0, we find that x = +4 for Sulfur.
Since the SO4-2 ions have two negative charges and oxygen atoms in almost all compounds have two negative charges each, the sulfur atoms have an oxidation number of -2 -4(-2) = +6.
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
The oxidation number of S in Na2SO4 is +6. This is because Na has an oxidation number of +1 and O has an oxidation number of -2. By setting up and solving an equation, we find that the oxidation number of S must be +6 to balance the charges in the compound.
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
In S2O82-, each S atom has an oxidation number of +5. In SO42-, the oxidation number of S is also +5. There is no change in oxidation number for sulfur when transitioning from S2O82- to SO42-.
The oxidation number of NCS is -1. N has an oxidation number of -3, while S has an oxidation number of +6 in the NCS molecule.
In SOCl2, the oxidation numbers are as follows: Sulfur (S) has an oxidation number of +4 Oxygen (O) has an oxidation number of -2 Chlorine (Cl) has an oxidation number of -1
+1 for H +6 for S -2 for each O