In CaSO4 (calcium sulfate), the oxidation number of calcium (Ca) is +2, as it typically forms ionic compounds with a 2+ charge. Oxygen (O) usually has an oxidation number of -2 in compounds, so in CaSO4, the total oxidation number of the oxygen atoms is -8. To find the oxidation number of sulfur (S), we can set up the equation: 2(+2) + x + 4(-2) = 0, where x represents the oxidation number of sulfur. Solving this equation gives us the oxidation number of sulfur as +6.
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.
Since the SO4-2 ions have two negative charges and oxygen atoms in almost all compounds have two negative charges each, the sulfur atoms have an oxidation number of -2 -4(-2) = +6.
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
+6
For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.
The only oxidation number is 2+.
Since the SO4-2 ions have two negative charges and oxygen atoms in almost all compounds have two negative charges each, the sulfur atoms have an oxidation number of -2 -4(-2) = +6.
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
In S2O82-, each S atom has an oxidation number of +5. In SO42-, the oxidation number of S is also +5. There is no change in oxidation number for sulfur when transitioning from S2O82- to SO42-.
The oxidation number of NCS is -1. N has an oxidation number of -3, while S has an oxidation number of +6 in the NCS molecule.
In SOCl2, the oxidation numbers are as follows: Sulfur (S) has an oxidation number of +4 Oxygen (O) has an oxidation number of -2 Chlorine (Cl) has an oxidation number of -1
+1 for H +6 for S -2 for each O