The full form of A.D. is Anno Domini and the full form of B.C. is Before Christ.
58 years are between 30 BC and AD 30. The first thing you need to remember is that there is no year 0; the year before AD 1 is 1 BC. So the years between 30 BC and AD 30 are... 29 BC, 28 BC, 27 BC, ..., 2 BC, 1 BC, AD1, AD 2, ..., AD 27, AD 28, AD 29 29 BC through 1 BC is 29 years, and AD 1 through AD 29 is 29 years. 29 years + 29 years = 58 years
BC = Before Christ. AD = Anno Domini (latin) the year of Christ's birth.
Yes. The simple answer is that rational fractions are infinitely dense. A longer proof follows:Suppose you have two fractions a/b and c/d where a, b, c and d are integers and b, d are positive integers.Without loss of generality, assume a/b < c/d.The inequality implies that ad < bc so that bc-ad>0 . . . . . . . . . . . . . . . . . . . (I)Consider (ad + bc)/(2bd)Then (ad+bc)/2bd - a/b = (ad+bc)/2bd - 2ad/2bd = (bc-ad)/2bdBy definition, b and d are positive so bd is positive and by result (I), the numerator is positive.That is to say, (ad+bc)/2bd - a/b > 0 or (ad+bc)/2bd > a/b.Similarly, by considering c/d - (ad+bc)/2bd is can be shown that c/d > (ad+bc)/2bd.Combining these results,a/b < (ad+bc)/2bd < c/d.
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
Suppose the two fractions are a/b and c/d ad that b, d > 0. Then cross multiplication gives ad and bc. If ad > bc then a/b > c/d, If ad = bc then a/b = c/d, and If ad < bc then a/b < c/d
The last date of BC was 1 BC, then the first date of AD was 1 AD, there was no zero.
Okay Will AD is older than BC because AD is very old not like BC
BC : before Christ AD : anno domino
58 years are between 30 BC and AD 30. The first thing you need to remember is that there is no year 0; the year before AD 1 is 1 BC. So the years between 30 BC and AD 30 are... 29 BC, 28 BC, 27 BC, ..., 2 BC, 1 BC, AD1, AD 2, ..., AD 27, AD 28, AD 29 29 BC through 1 BC is 29 years, and AD 1 through AD 29 is 29 years. 29 years + 29 years = 58 years
It isn't a question of closer to ad or bc, it IS bc. 3000bc would be -3000ad.
Nothing. There was no time period between BC and AD. 1 BC was followed by 1 AD. There was no year zero or any gap between BC and AD.
bc comes first because bc stands for before christ
Ad because bc started after
BC= negative number AD= Positive number
BC is before AD (Before Christ) (After Death)
BC - Before Christ AD - Anno Domini
AD