Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:
(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3
394.794 grams
The answer is 20,664 g ammonia.
1.60 x 10^24 molecules
106.7 grams
1.88*10^24
This value is 21,85 g.
There are 6.02x10^23 molecules in one mole of anything.
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
there would be 50 grams of ammonia will be formed
2
34 grams of Ammonia
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
394.794 grams
3 moles of ammonia is 51grams. One mole is 17 grams.
Ammonia has the chemical formula NH3, and thus there are three hydrogen atoms in a molecule of ammonia.
Quite a few! 170 grams ammonia (1 mole NH3/17.034 grams)(6.022 X 1023/1 mole NH3) = 6.01 X 1024 atoms of ammonia ========================
16.0 g