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Chlorine gas occupies a volume of 25 mL at 300K What volume it occupy at 600k
4 g of helium occupies 22.414 liters So, 0.8 g will occupy 4.483 liters
4 g of helium occupy 22.414 liters. So, 84.6 g of helium occupy 474.056 liters.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
4 g (1 mole) of helium will occupy 22.414 liters. So, 15 g will occupy 84.05 liters
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
1mol of a gas occupies 24 dm3 at STP, so 2.2mol X 24 mol/dm3 =52.8dm3 or 5280cm3
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
Volume = how much space an object occupies, that nothing else can occupy at the same time.
Volume = how much space an object occupies, that nothing else can occupy at the same time.
5.6