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Anamika Pandey

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3y ago

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How many molecules OS CO2 are present in 51.5 of CO2?

2.65 mol * 64.07 g/mol = 169.79 g


If a balloon contains 0.15 moles of CO2 gas. how many molecules of CO2 are in the balloon?

The number of molecules is 0,90332112855.10e23.


How many molecules are in 4co2?

2.75 x 1024molecules of CO2


How many co2 molecules are produced in the cytoplasm in the end of glycosis?

The number is zero.No CO2 is produced in glycolisis.


How many molecules of H2O and CO2 can be made from 4 molecules of CH4 and excess O2?

The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O


How molecules are in 2.4 moles of CO2?

1 mole CO2 = 6.022 x 1023 molecules 2.4mol CO2 x 6.022 x 1023 molecules CO2/1mol CO2 = 1.4 x 1024 molecules CO2


How many molecules of CO2 used to produce one glucose?

4


When glucose is broken down how many molecules of CO2 are formed?

6


How many molecules of CO2 are fixed to form one molecule of glucose?

6 CO2 + 6 H2O →C6H12O6 + 6 O2Carbon dioxide + Water + Light energy → Glucose + Oxygen6 molecules of CO2


How many molecules are in 6.30 mol CO2?

There are 3.80 x 10^24 molecules of CO2 in 6.30 mol. This can be calculated by using Avogadro's number, which is 6.022 x 10^23 molecules/mol.


How many molecules of CO2 are present in 33.6g of CO2?

To find the number of molecules in 33.6g of CO2, you first need to convert grams to moles. The molar mass of CO2 is 44 g/mol. Therefore, 33.6g is equal to 33.6g / 44 g/mol = 0.764 moles of CO2. Using Avogadro's number (6.022 x 10^23 molecules/mol), you can calculate that 0.764 moles of CO2 is equal to 0.764 mol x 6.022 x 10^23 molecules/mol = 4.6 x 10^23 molecules of CO2.


3920 molecules CO2 to moles CO2?

We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.