8.066
2.65 mol * 64.07 g/mol = 169.79 g
The number of molecules is 0,90332112855.10e23.
2.75 x 1024molecules of CO2
The number is zero.No CO2 is produced in glycolisis.
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
1 mole CO2 = 6.022 x 1023 molecules 2.4mol CO2 x 6.022 x 1023 molecules CO2/1mol CO2 = 1.4 x 1024 molecules CO2
4
6
6 CO2 + 6 H2O →C6H12O6 + 6 O2Carbon dioxide + Water + Light energy → Glucose + Oxygen6 molecules of CO2
There are 3.80 x 10^24 molecules of CO2 in 6.30 mol. This can be calculated by using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
To find the number of molecules in 33.6g of CO2, you first need to convert grams to moles. The molar mass of CO2 is 44 g/mol. Therefore, 33.6g is equal to 33.6g / 44 g/mol = 0.764 moles of CO2. Using Avogadro's number (6.022 x 10^23 molecules/mol), you can calculate that 0.764 moles of CO2 is equal to 0.764 mol x 6.022 x 10^23 molecules/mol = 4.6 x 10^23 molecules of CO2.
We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.