The notation "3 CO2" indicates that there are three molecules of carbon dioxide (CO2). Therefore, in 3 CO2, there are exactly three molecules of CO2 present. Each molecule consists of one carbon atom and two oxygen atoms, but the question specifically asks about the number of molecules.
No, the chemical equation is not balanced. It should be: 2Fe2O3 + 3C -> 4Fe + 3CO2.
3CO₂ is a chemical formula, not a symbol. It represents three molecules of carbon dioxide, where "CO₂" indicates one molecule of carbon dioxide composed of one carbon atom and two oxygen atoms. The "3" in front signifies that there are three such molecules present.
C3H8 + 5O2 -> 3CO2 + 4H2O That is the complete combustion for Propane.
C-carbon H-hydrogen O-oxygen Three different elements.
Combustion of propaneC3H8 + 5O2 ==> 3CO2 + 4H2OWhat is the question?
The balanced chemical equation for the combustion of propane (C3H8) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
"CO2" is carbon dioxide. The three in front indicates that there are three molecules of the compound. Usually you wouldn't see 3CO2 on its own, you would just see CO2 or carbon dioxide. The only time a coefficient (the three in this case) is given is when an equation is being balanced.
No, the chemical equation is not balanced. It should be: 2Fe2O3 + 3C -> 4Fe + 3CO2.
The balanced chemical equation for this reaction is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
3CO₂ is a chemical formula, not a symbol. It represents three molecules of carbon dioxide, where "CO₂" indicates one molecule of carbon dioxide composed of one carbon atom and two oxygen atoms. The "3" in front signifies that there are three such molecules present.
C3H8 + 5O2 -> 3CO2 + 4H2O That is the complete combustion for Propane.
C3h8+ 5o2---> 3co2+ 4h2o
Yes, it is correct.C3H8 + 5 O2 = 3 CO2 + 4 H2O
C-carbon H-hydrogen O-oxygen Three different elements.
Coefficients :)
C3H8 + 5O2 --> 3CO2 + 4H2O
The equation you provided is not balanced. To balance it, you need to make sure that the number of each type of atom is the same on both sides of the equation. Once the equation is balanced, you can count the number of reactions by looking at the coefficients of the reactants and products in the balanced equation.