No, the chemical equation is not balanced. It should be: 2Fe2O3 + 3C -> 4Fe + 3CO2.
C3H8 + 5O2 -> 3CO2 + 4H2O That is the complete combustion for Propane.
C-carbon H-hydrogen O-oxygen Three different elements.
Combustion of propaneC3H8 + 5O2 ==> 3CO2 + 4H2OWhat is the question?
1 x 1024 molecules
The balanced chemical equation for the combustion of propane (C3H8) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
"CO2" is carbon dioxide. The three in front indicates that there are three molecules of the compound. Usually you wouldn't see 3CO2 on its own, you would just see CO2 or carbon dioxide. The only time a coefficient (the three in this case) is given is when an equation is being balanced.
No, the chemical equation is not balanced. It should be: 2Fe2O3 + 3C -> 4Fe + 3CO2.
The balanced chemical equation for this reaction is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
C3H8 + 5O2 -> 3CO2 + 4H2O That is the complete combustion for Propane.
C3h8+ 5o2---> 3co2+ 4h2o
Yes, it is correct.C3H8 + 5 O2 = 3 CO2 + 4 H2O
Coefficients :)
C3H8 + 5O2 --> 3CO2 + 4H2O
C-carbon H-hydrogen O-oxygen Three different elements.
The equation you provided is not balanced. To balance it, you need to make sure that the number of each type of atom is the same on both sides of the equation. Once the equation is balanced, you can count the number of reactions by looking at the coefficients of the reactants and products in the balanced equation.
C3H8 (g) + 5O2 (g) --> 3CO2 (g) + 4H2O (g) is the chemical equation for the combustion of propane.