2 ½ g or 2.5 g
(Explanation): If we start with 10 grams of cesium and the half-life is 2 years, then that means in 4 years we go through 2 half-lives. After the first half-life, divide 10 by 2 to get only 5 grams of cesium left. Divide that by 2 again to get amount left over after second half-life, which is 2 ½ or 2.5 grams.
5g would remain
I suppose that you think to the radioactive isotope Cs-17; After 4 years remain 9,122 g.
The half-life of cesium-137 is approximately 30.1 years, not 2 years. After one half-life, 5 G of the original 10 G sample would remain. After two half-lives (about 60.2 years), 2.5 G would remain, and so on. If you meant a hypothetical isotope with a 2-year half-life, after 2 years, 5 G would remain, and after 4 years, 2.5 G would remain.
2 1/2 g
2 1/2 g
2 1/2 g
After 6 years, approximately 5 grams of cesium-137 would remain from a 10 g sample due to its half-life of around 30 years. This decay is exponential, with about half of the original sample decaying every 30 years.
2 1/2 g
2 1/2 g
1 1/4 g (apex)or 1.25 g
If the substance has a half-life of 10 years, there would be 10 half-lives in a 100-year span. Each half-life reduces the amount by half, so after 100 years, 1/2^10 = 1/1024 grams of the sample would remain.
11/4 g apex