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CH3 is the empirical formula of C2H6; this molecule is an alkane commonly known as ethane.
C2.5 H1 O2
There are then 1.07 grams of oxygen in the sample (1.07 + .13 + .8 = 2.0). Carbon has a molar mass of 6, oxygen is 8 and hydrogen is 1. This gives the molar ration of C:H:O at about 0.8/6:0.13/1:1.07/8, reduced to .13:.13:.13. Thus the empirical formula is CHO.
moles C = 0.260 g C x 1 mol/12 g = 0.0217 moles Cmoles O = 0.347 g O x 1 mol/16 g = 0.0217 moles Omoles Cl = 1.537 g Cl x 1 mol/35.5 g = 0.043 moles Clmole ratio = 1C : 1O : 2Cl so empirical formula = COCl2
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
Kc2o4
get grams to moles, then divide each mol by the smallest mol. in htis case, you'd get, F4Sn.
CaBr2
This compound is potassium oxide, K2O.
CH3 is the empirical formula of C2H6; this molecule is an alkane commonly known as ethane.
C2.5 H1 O2
The empirical formula for CaCl2 is CaCl2...you cannot simplify it any furthur.
if you have a water sample that contains either nitrate chloride.
ch2o and c6h12o6
sample
Radiometric dating.
There are then 1.07 grams of oxygen in the sample (1.07 + .13 + .8 = 2.0). Carbon has a molar mass of 6, oxygen is 8 and hydrogen is 1. This gives the molar ration of C:H:O at about 0.8/6:0.13/1:1.07/8, reduced to .13:.13:.13. Thus the empirical formula is CHO.