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How are functions invoked in cpp?

Updated: 12/16/2022
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If the function is inline expanded then it is not invoked at all -- there is no function call. However, if the function is not or cannot be inline expanded, a procedure call is invoked. This pushes the calling function's local values onto the stack, followed by the return address, followed by the callee's argument values in reverse order. Control is then passed to the address of the function. The function then pops the arguments off the stack and assigns them to its local parameters (parameters that are passed by value will automatically invoke the copy constructors of those parameters). The function then executes. When a return statement is encountered, the return address is popped from the stack, the return value (if any) is pushed onto the stack, and control is passed to the return address. When a function returns, the return value (if any) and the local values are popped from the stack, and execution continues from where it left off.

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Q: How are functions invoked in cpp?
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How do you invoke the constructor function in c plus plus?

There is no such thing as a constructor function in C++ (constructors have no return value, not even void, and cannot be called like regular functions). Constructors are invoked rather than called directly, either by declaring a static variable of the class type, or via the C++ new operator.


Why you divide a program into functions?

In order to make a large program more manageable, it is convenient to identify and isolate specific tasks that a program performs and to separate out those tasks into functions. These functions are used/invoked as needed by the main part of the program. They can also be invoked by other functions. Often a program will perform the same task in different parts of the program. Using a function to perform the task and invoking the function from the different parts of the program means that only one copy of the code is needed. This helps reduce the size of the program.


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Can a static function be made virtual?

No. Virtual functions are invoked according to the runtime type of the object. That is; the most-derived override is automatically invoked even when the runtime type of the object cannot be determined at compile time. This is achieved through the object's virtual table. Static methods do not have any object associated with them; they can be invoked even when no object of the type exists. Without an object, there can be no virtual table. Thus static functions cannot be virtual. They are mutually exclusive concepts.

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