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The cell of Gram+ bacteria will break down against lysozyme and the cell will be injured but when it placed in sucrose the nutrient will be absorbed by the surface
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
Add 10 g to a volumetric flask and make up to the 1 liter mark.
1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams
about 1.4*10^25
Take 10 gm oF KI dissolve it in 100ml.
The cell of Gram+ bacteria will break down against lysozyme and the cell will be injured but when it placed in sucrose the nutrient will be absorbed by the surface
It has been confirmed that only 10% is true
300 ml
25.263157895 g @ 10 % + 94.736842105 g @ 0.5 % = total 3 g out of 120 g total = 2.5 %
10%
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
Add 10 g to a volumetric flask and make up to the 1 liter mark.
about 1.4*10^25
1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams
Molarity=[w/GMW]*[1000/volume(in mL)] 0.5=[w/342]*[1000/100]=17.1g similarly,34.2g sucrose is to dissolved in water and made up to 100mL to make 1molar solution and 171g to make 5molar solution.
.05 L x 342 (this is the molecular weight of sucrose) x 1.75 = 29.925g