Depending on your experiment, the number of moles will or will not change. If the gas is in a sealed container, then obviously the number of moles does not change. But if the gas is in an open container, then the gas is free to move.
In this case, raising the temperature would cause the number of moles to go down. Because the temperature is going up, the pressure increases also. When the pressure goes up, the volume goes up, meaning the gas "wants" to spread out. In an unsealed container, the gas will leave and you will end up with less moles within the container.
The relationship between volume and moles can be shown by using the Ideal Gas Law:
The volume occupied by a gas at a specified temperature and pressure is directly proportional to the number of particles in a gas.
Formula: PV = nRT
Where P = pressure
V = volume in liters
T = temperature
n = the number of particles in moles
R = the gas constant, and depends on the units of pressure:
use 0.0821 if pressure is in atmospheres (atm),
use 62.4 if pressure is in millimeters of Mercury (mmHg),
or 8.31 if pressure is in kiloPascals (kPa).
Yes, the number of moles (n) of a gas is related to the pressure (P), volume (V) and temperature (T), by the ideal gas law: PV = nRT
So, moles (n) = PV/RT (where R is the universal gas constant)
1 mole is equivalent to 22,414 L; and 1 mole has a number of molecules equal to the Avogadro number.
You think probable to the relation: pV = nRT.
This is the general law of gases: pV=nRt
It goes up
In a sample of air, an increase in temperature will result in an increase in the partial pressure of oxygen.
If a fixed sample of gas has a change of temperature pressure would increase.
liquid
The frequency of collisions is reduced
Boyle found that when the pressure of a gas at constant temperature is increased the volume of a gas decreases. P x V is a constant at constant Temperature Boyle's Law: P1V1 = P2V2
In a sample of air, an increase in temperature will result in an increase in the partial pressure of oxygen.
If a fixed sample of gas has a change of temperature pressure would increase.
cos2(s)
liquid
temperature
The temperature of the water is 100 degrees celsius.
For the pressure to remain the same, the temperature would double if the volume also doubled.
A sample of gas occupies 1.55L at STP. What will the volume be if the pressure is increased to 50 atm while the temperature remains constant?
Increases in direct proportion to the increase in temperature (on an absolute scale).
temperature increase The pressure of a contained sample of gas can be increased by increasing its temperature, or by decreasing its volume, or by injecting additional mass into it.
See the Related Question (link to the left of this answer)."How many moles of carbon dioxide are there in a 50.0 dm3 sample of the gas at a pressure of 100.0 kPa and a temperature of 50 degrees celsius?" 1.86 moles
The critical temperature for carbon dioxide is 304K (87.8°F [31°C]). That means that no amount of pressure applied to a sample of carbon dioxide gas at or above 304K (87.8°F [31°C]) will cause the gas to liquefy. At or below that temperature, however, the gas can be liquefied provided sufficient pressure is applied. The corresponding critical pressure for carbon dioxide at 304K (87.8°F [31°C]) is 72.9 atmospheres (~73000 kPa). In other words, the application of a pressure of 72.9 atmospheres of pressure on a sample of carbon dioxide gas at 304K (87.8°F [31°C]) will cause the gas to liquefy. See related link to read more about the Liquefaction of Gases.