You divide the number of atoms by avagadro's number. Avagadro's number is 6.022x10^23 atoms/molecules / mole. The best way to remember this is by the units, atoms in each mole.
Approx 3.13*10^25 atoms.
9 g anhydrous magnesium nitrate = 0,061 mol
1 mole of helium has 6.023 x 1023 atoms. So, 1.5 mole of helium will have 9.035 x 1023 atoms.
3.9 moles of atoms
This is equivalent to 1,4 moles.
Divide it by Avogadro constant.There are 0.0088 moles
Approx 3.13*10^25 atoms.
To determine the number of atoms of chlorine in 445g of lead chloride (PbCl2), you need to calculate the number of moles of PbCl2 in 445g and then multiply it by the number of chlorine atoms in one PbCl2 molecule. First, calculate the number of moles of PbCl2 using the formula: moles = mass / molar mass. The molar mass of PbCl2 is 278.1 g/mol, so moles = 445g / 278.1 g/mol = 1.6 moles. Since there are two chlorine atoms in one molecule of PbCl2, the total number of chlorine atoms is 2 * 1.6 moles = 3.2 moles of chlorine atoms. To convert moles to atoms, multiply by Avogadro's number. Therefore, there are 3.2 moles * 6.022 x 10^23 atoms/mole = 1.9264 x 10^24 atoms of chlorine in 445g of PbCl2.
9 g anhydrous magnesium nitrate = 0,061 mol
1 mole of helium has 6.023 x 1023 atoms. So, 1.5 mole of helium will have 9.035 x 1023 atoms.
44 moles of atoms
1,638 moles contain 9,864266723766.10e23 atoms.
3.9 moles of atoms
One mole of any mono-atomic element contains (by definition) 6.022*10+23 atoms. please calculate from there by multiplying - 9,334.1023 atoms.
One mole of any mono-atomic element contains (by definition) 6.022*10+23 atoms. please calculate from there by multiplying - 11,14.1023 atoms.
3,00 moles of Li have 18,066422571.10e23 atoms.
This is equivalent to 1,4 moles.