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weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution. Reasons:N is short for NORMAL SOLUTIONS, The definition of a NORMAL SOLUTION is a solution that contains 1 gram equivalent weight (gEW) per liter solution. An equivalent weight is equal to the molecular weight divided by the valence (replaceable H ions). eg:1N NaCl = 58.5 g/L 1N HCl = 36.5 g/L 1N H2S04 = 49 g/L Problems involving normality are worked the same as those involving molarity but the valence must be considered: 1N HCL the MW= 36.5 the EW = 36.5 and 1N would be 36.5g/L 1N H2SO4 the MW = 98 the EW = 49 and 1N would be 49 g/L 1N H3PO4 the MW = 98 the EW = 32.7 and 1N would be 32.7 g/L so,u can weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution.

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15y ago
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11y ago

The principle of dilution should be used here. The procedure should be to reduce the concentration of nitric acid by 65 times. Therefore, it should be diluted with the ratio of 1:64 between 65% nitric acid and distilled water respectively.

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10y ago

how to prepare 10% nitric acid from 55% nitric acid

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13y ago

(1000 mL)*0.01n / 18n = 0.55 mL concentrated Nitric acid (18M) to be added in 1000 mL distilled water.

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14y ago

By solving 400 g sodium hydroxide in 1L of water (with care).

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Q: How do you prepare the 10N HCl solution?
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