3.6ml of HCl is diluted and make it into 500ml with distilled water.
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Add 50 mL of HCl 1 N in a 1 L volumetric flask, class A or B; add ca. 900 mL distilled water to the flask. Place the flask in a thermostat at 20 0C. After 30 min add slowly distilled water to the mark (1 L) and stir well the closed flask. Pour the solution in a bottle. Place a label with the date, concentration, name of the solution on the bottle.
It depends on the volume required of the final solution that is 0.25 N
Look at the bottle of HCl. It gives a molarity. then dilute to 0.25 M.
how do u prepare 0.1N HCL from 37% Hcl
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
935ml
combine 100 mL 6 M HCl with 500 mL H2O
1
85 mL of (concentrated, 38%) HCl solution contains 36.5 gram HCl, which dissolved and diluted in up to 1.0 Liter gives you an 1.0 molar solution.
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
935ml
Molar mass of HCl = 1 + 35.5 = 36.5 Number of moles of HCl = mass / molar mass = 85.6 / 36.5 = 2.345 moles Molarity = number of moles / Volume = 2.345 / 0.385 = 6.091 M
combine 100 mL 6 M HCl with 500 mL H2O
1
pH = -log(0.280) = 0.553
85 mL of (concentrated, 38%) HCl solution contains 36.5 gram HCl, which dissolved and diluted in up to 1.0 Liter gives you an 1.0 molar solution.
0.17 Molar
Get two moles of HCl and add water until the solution is 1 L
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
When 100cm3 of 1.0 molar of sodium hydoxide solution at 200oc was added to 100cm3of1.0 molar of HCL solution at 200oc,then the temperature of HCL rose to 26.8oc.calculate the standard heat of neutralisation?(Given that the specific heat capacity of water is 4.2KJg-1k-1)
6g Tris HCl + 100ml dH2O, pH 6.8