Get two moles of HCl and add water until the solution is 1 L
The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).
A 0.1N (Normal) HCl solution is equivalent to a 0.1M (Molar) concentration of HCl. This means that there is 0.1 moles of HCl per liter of solution. So, the percentage concentration of a 0.1N HCl solution would be 0.1%.
The pH of a 0.1 molar aqueous solution of HCl would be 1. This is because HCl is a strong acid that completely dissociates in water to produce H+ ions, resulting in a high concentration of H+ ions in solution, leading to a low pH value.
The pH of a 0.00001 molar HCl solution is 5. HCl is a strong acid, and at this concentration, it would dissociate almost completely in water to produce H+ ions, resulting in a pH of 5.
0.1 molar HCl means that there is 0.1 moles of hydrochloric acid dissolved in 1 liter of solution. It indicates the concentration of the acid in the solution, with molarity representing the number of moles of solute per liter of solution.
The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).
A 0.1N (Normal) HCl solution is equivalent to a 0.1M (Molar) concentration of HCl. This means that there is 0.1 moles of HCl per liter of solution. So, the percentage concentration of a 0.1N HCl solution would be 0.1%.
The pH of a 0.1 molar aqueous solution of HCl would be 1. This is because HCl is a strong acid that completely dissociates in water to produce H+ ions, resulting in a high concentration of H+ ions in solution, leading to a low pH value.
The pH of a 0.00001 molar HCl solution is 5. HCl is a strong acid, and at this concentration, it would dissociate almost completely in water to produce H+ ions, resulting in a pH of 5.
0.1 molar HCl means that there is 0.1 moles of hydrochloric acid dissolved in 1 liter of solution. It indicates the concentration of the acid in the solution, with molarity representing the number of moles of solute per liter of solution.
6N HCl refers to a 6 molar solution of hydrochloric acid. The strength of the acid solution is determined by its concentration. It is a moderately strong acid that can cause skin irritation and burns upon contact.
I'm not certain what is meant by 38 HCl, but I suspect it must mean 38% HCl. Typically, concentrated Hydrochloric Acid is about 36-38%. 38% W/W means each 100 grams of 38% HCl contains 38 grams of dissolved hydrogen chloride gas. Generally, concentrated HCl is considered to by 12 Formal (or less correctly, 12 Molar) which is equivalent to 12 Normal. A close approximation of 0.5M would be as follows, using a Volume/Volume prep: Combine 11.5 parts water and add 0.5 parts 12 Molar HCl. For example: 115 mL of water plus 5 mL of 12 M HCl.
To find the mole fraction of HCl in the solution, we first need to calculate the molar mass of HCl (H=1g/mol, Cl=35.5g/mol). Then, determine the number of moles of HCl in 100g of the solution. Finally, calculate the mole fraction of HCl by dividing the moles of HCl by the total moles of solute and solvent in the solution.
All you have to do is convert the 6.5 g HCl solution into moles, and then plug that value into the molarity formula. If you need help, here are the formulas: # mol = (mass of substance)/(molar mass) - the molar mass is just the molecular mass of the substance expressed in grams :) Molarity (M) = (# mol solute)/(# L solution) - the solute, in this case, is the HCl, and the solution is just one, based on your question Happy Calculating!!!
To make a 2 molar solution of hydrochloric acid, you would need to know the volume of the solution you want to make. Once you have the volume, you can use the molarity formula (M = moles of solute / liters of solution) to calculate the grams of hydrochloric acid needed.
The pH of a 0.280 M HCl solution is approximately 0.55. This is because HCl is a strong acid that dissociates completely in solution to produce H+ ions, leading to a low pH value.
Take 83.3 mL and add water up to 1000 mL (12 times as much) The above only helps in one situation... here is the way to do it for any situation Litersc * Molesc / Litersc = Litersd * Molesd / Litersd where subscript c is concentrated and subscript d is dillute. The quicker way to write it is C1V1 = C2V2 so if you are going from 12M and want to go to 1M then it would be: 12M*V1 = 1M*1L Rearrange and solve: V1 = 1ML/12M = 0.0833 L = 83.3 mL