C. 5
1
The pH scale is a convenient method for expressing the hydronium ion concentration of a solution. pH = log(1/[H+]) = -log [H+]. [H+] is the hydronium ion concentration in M (molarity), which is the number of moles of solute per liter of solution.
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
the PH will be the same
pH = - log[H+] so a 0.01 M solution of HCl has, pH= 2
pH = -log(0.280) = 0.553
1
The pH scale is a convenient method for expressing the hydronium ion concentration of a solution. pH = log(1/[H+]) = -log [H+]. [H+] is the hydronium ion concentration in M (molarity), which is the number of moles of solute per liter of solution.
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
No. pH is a log scale. You can't have a pH of zero. ---- Above answer left in to correct a misconception. Yes, you certainly can have a pH of zero. A 1 molar solution of a strong acid has a pH of zero, and stock HCl (roughly 12 molar) has a pH of about -1.1 or so. pH is the negative log of the hydrogen/hydronium ion concentration, which for a strong acid is approximately the same as the acid concentration. The log of 1 is zero, therefore the pH of a 1 molar solution of a strong acid is zero. The log of 10 is 1, therefore the pH of a 10 molar solution of a strong acid is -1.
the PH will be the same
pH = - log[H+] so a 0.01 M solution of HCl has, pH= 2
its PH is 3
Ph gives the hint about the proton gradient of the solution as pH=-log[H+] we need the inforamtion of the molecular composition of the solution to know about the molar mass. Ph gives the hint about the proton gradient of the solution as pH=-log[H+] we need the inforamtion of the molecular composition of the solution to know about the molar mass.
Its pH value is 2.
- log(0.00450 M HCl)= 2.3 pH=======
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990