No, it acts on different bodies. If a body does a force on another body, the second body will exert a force with the same magnitude and opposite direction on the first body.
So for example, if you kick a football, you use a force on the ball, which causes the ball to accelerate and move. At the same time, the ball exerts an equal force on your foot, though the effect isn't quite the same as with the ball. (The reason you don't move yourself, is because the acceleration is also dependent on the mass of the body (F=m.a -> a=F/m). So the bigger the mass, the smaller the acceleration.)
The two forces from the example act on different bodies: the action force on the ball and the reaction force on your foot. This is very important to remember in exercices, because otherwise you'll assign forces to the wrong bodies!
I hope I helped you out a bit!
When one body exerts a force on another body, the other body exerts an equal and opposite reaction force. Both bodies gain equal and opposite momentum due to the forces. The momentum gained by a body due to the action of a force on it a force is given by the integral of the force with respect to time over the time period that it acts. In less mathematical terms, the momentum gained is dependant on how the strength of the force changed over the time it acted and also how long it acted for.
How much the two bodies move as a result is dependant on their respective masses. If a body has momentum, p, and mass, m, then it's velocity, v, due to that momentum is given by
v=p/m,
so the larger a body's mass, the smaller its velocity for a given momentum and the smaller it's mass, the greater its velocity. If the two bodies have similar masses, they will move in opposite directions with similar speeds; For example, two billiard balls colliding. However if one body has a much larger mass, it will move much less than the smaller body. An example of this would be doing a pushup; You exert a force on the Earth and it exerts an equal and opposite reaction force on you. You both gain the same amount of momentum from the pushup but, because the Earth's mass is so much greater than yours, you move up a noticeable amount while the Earth barely moves down at all.
The force acting on an object "A" from outside is action force , and the reaction force is the force exerted by A to the outside object .
Therefore, it is obvious that action force and the corresponding reaction force cannot act on one and the same body.
When action reaction forces are unbalanced, they produce motion.
An equal but opposite force will be exerted toward the first force.
both the forces act on same body
Simple answer: No
No. They acts on same body. So they do not constitute action-reaction pair.
yes
Any pair of forces that has the same magnitude (strength) and opposite direction. For example, when putting an object on atablet (a puppy) Gravity acts upon the puppy to pull it down but it doesn't go down because there is a force that the table is acting on the puppy, with the same magnitude as the gravity but the direction is upward. => equilibrium forces.
A extra pair of hands would work. The more force
2 pairs of limbs. One pair of feet and one pair of arms.
When a pair of balanced forces acts on an object, the net force that results is equal to zero.
Zero.
The net force is zero.
No, they act on different bodies. For example if "A" attracts "B", then "B" also attracts "A".
If the net force is zero, then the forces are balanced. If the net force is not zero, then the forces are not balanced. You can have a balanced pair of forces, but not a pair of balanced forces.
the answer is zero.
It is zero.It is always ZERO.=)
a) Centrifugal force is not even a real force, it is a fictitious force. b) Action and reaction forces act on DIFFERENT objects. If A acts on B, then B acts on A.
No. They acts on same body. So they do not constitute action-reaction pair.
No. "Action-reaction pair" implies that if an object "A" acts on object "B", then object "B" will also act on object "A". This isn't the case here.
The input force or the effort on a pair of scissors would be the force applied by your hands on the handles. The output force or load would be the blades of the pair of scissors.
what is the anologous pair in force current anology