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yes the number of moles is the the number before the substance for example if the equation is balanced and you want to find H2O and it appears like 3H2O in the equation then their are 3 moles of H2O
first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles. first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles.
the moles of the reactants and products
Balanced equation. 2C8H18 + 25O2 -> 16CO2 + 18H2O 5.5 moles C8H18 (25 moles O2/2 moles C8H18) = 68.75 moles O2 needed
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2
The information in a balanced chemical equation shows how many moles of a reactant are involved in a reaction is the number appearing immediately before the formula for the reactant in question in the chemical equation. This number is called a "coefficient".
Titration equation can be solved by following the steps below: 1. write a well balanced equation. 2. Calculate number of moles of standard solution that is in the solution. 3. User molar relationship to convert moles of standard solution to that of unknown solution. 4. Find the number of moles of unknown solution.
yes the number of moles is the the number before the substance for example if the equation is balanced and you want to find H2O and it appears like 3H2O in the equation then their are 3 moles of H2O
Titration equation can be solved by following the steps below: 1. write a well balanced equation. 2. Calculate number of moles of standard solution that is in the solution. 3. User molar relationship to convert moles of standard solution to that of unknown solution. 4. Find the number of moles of unknown solution.
first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles. first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles.
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
the moles of the reactants and products
3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
H2o
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
Balanced equation. 2C8H18 + 25O2 -> 16CO2 + 18H2O 5.5 moles C8H18 (25 moles O2/2 moles C8H18) = 68.75 moles O2 needed
Balanced equation. 2S + 3O2 --> 2SO3 1.32 moles O2 (2 moles SO3/3 moles O2) = 0.880 moles sulfur trioxide produced ========================