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To set up the equation for the moles of chalk, you first need to determine the molar mass of the main component of chalk, which is calcium carbonate (CaCO₃). The molar mass is approximately 100.09 g/mol. Then, find the mass of a single piece of chalk, and divide the molar mass by that mass to calculate how many pieces of chalk are needed to equal one mole. The equation can be expressed as: Number of pieces = (100.09 g/mol) / (mass of one piece of chalk in grams).

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2mo ago

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How many moles in a teaspoon of chalk?

The molecular weight(M) of chalk(CaCO3) = (40+12+48)g/mol =100g/mol and teaspoon (m)= 4.93g We know, n=m/M So, n= (4.93/100) mol = .0493 mol To find out number of molecules we use, N= n x NA equation. N= .0493 mol x 6.02 x 1023 molecules/mol =2.968 x 1022 molecules Therefore, there are 2.968 x 1022 molecules in a teaspoon of chalk.


What information in a balanced chemical equation shows how many moles of a reactant are involved in a reaction?

The information in a balanced chemical equation shows how many moles of a reactant are involved in a reaction is the number appearing immediately before the formula for the reactant in question in the chemical equation. This number is called a "coefficient".


How do you solve this question?

Titration equation can be solved by following the steps below: 1. write a well balanced equation. 2. Calculate number of moles of standard solution that is in the solution. 3. User molar relationship to convert moles of standard solution to that of unknown solution. 4. Find the number of moles of unknown solution.


What is the mole ratio that can convert from moles of a to moles of b?

The mole ratio to convert from moles of a to moles of b is determined by the coefficients of a and b in the balanced chemical equation. For example, if the balanced equation is 2A + 3B -> 4C, the mole ratio would be 3 moles of B for every 2 moles of A.


Use the following balanced equation to answer these question n2h4 plus 2h2o2--n2 plus 4h2o how many moles of h2o are produced from 1.5 moles of n2h4?

N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced


How would you find the answer to this question How many moles of HCl can be formed when moles of hydrogen gas react with chlorine?

You can determine the moles of HCl formed by using a balanced chemical equation for the reaction between hydrogen gas and chlorine. Calculate the stoichiometric ratio of hydrogen to HCl in the balanced equation to determine the moles of HCl formed from the given moles of hydrogen gas.


How many moles of nh3 are produced from 1.5 moles h2?

The balanced chemical equation for the reaction is: 3H2 + N2 -> 2NH3 From the stoichiometry of the balanced equation, 3 moles of H2 produces 2 moles of NH3. Therefore, if you have 1.5 moles of H2, you will produce 1.5 moles * (2 moles NH3 / 3 moles H2) = 1 mole of NH3.


How many moles of Na are needed to make 4 moles of H2?

It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written


What is the ratio of moles of CuSO4 to moles of NaOH?

This ratio is 1:2.


How do you find the amount of precipitate in a saturated solution?

first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles. first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles.


How many moles of oxygen are needed to react completely with 2.3 moles of H2S?

The balanced chemical equation for the reaction between oxygen (O2) and hydrogen sulfide (H2S) is: 2H2S + 3O2 -> 2SO2 + 2H2O From the equation, it is a 3:2 ratio of O2 to H2S. Therefore, if 2.3 moles of H2S are present, (2.3 moles H2S) * (3 moles O2 / 2 moles H2S) = 3.45 moles of O2 are needed.


How many moles of O2 are required to react with 23.5 moles of methanol?

Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------