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The molecular weight(M) of chalk(CaCO3) = (40+12+48)g/mol =100g/mol

and teaspoon (m)= 4.93g

We know, n=m/M

So, n= (4.93/100) mol = .0493 mol

To find out number of molecules we use, N= n x NA equation.

N= .0493 mol x 6.02 x 1023 molecules/mol

=2.968 x 1022 molecules

Therefore, there are 2.968 x 1022 molecules in a teaspoon of chalk.

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11y ago

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