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Put a 2 to NH3 first.Then a 3 to Hydrogen.
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How many molecules of H2 react with each molecule of N2?
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
Stoichiometry grams of N2 are needed to produce 20 grams NH3 N2 plus H2 NH3?
16,45 g nitrogen are needed.
How many moles of NH3 can be produced from 12.0mol of H2 and excess N2?
8 mol
How do you balance this equation N2 plus H2 to NH3 plus N2?
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
Is nitrogen combing with hydrogen a chemical reaction?
Of course; 3 H2 + N2 -------2 NH3
How do you balance N2 plus H2yeildsNH3?
(N2) + 3(H2) = 2(NH3)
What elements are oxidized and what are element are reduced N2 H2--NH3?
H2 n2
What the answer n2 plus h2 plus nh3?
Ammonia
What is pure ammonia?
NH3 is made by N2 and H2. pure NH3 is clean ammonia.
How many molecules of H2 react with each molecule of N2?
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
Stoichiometry grams of N2 are needed to produce 20 grams NH3 N2 plus H2 NH3?
16,45 g nitrogen are needed.
N2 plus 3H2 -- 2NH3 If you produce 55.5 grams of ammonia how many grams of nitrogen will you need?
You need the balanced chemical equation for N2 and H2 combining to form ammonia, NH3.N2 (g) + 3 H2 (g) -----> 2 NH3 (g)Moles NH3 = ( 55.5 g NH3 ) / ( 17.03 g/mol NH3 ) = 3.259 moles of NH3n N2 required = ( 3.259 mol NH3 ) ( 1 N2 mol / 2 NH3 mol ) = 1.629 moles N2m N2 required = ( 1.629 mol N2 ) ( 28.103 g N2 / mol N2 ) = 45.67 g N2 needed
Write an equation for the formation of NH3 g from its elements in its standard states?
1/2 n2 + 3/2 h2 = nh3 sorry about the lower case they wouldn't let me summit it with caps N2 + 3 H2 => 2 NH3
Is h2 plus n2-nh3 single replacement?
This is a synthesis reaction.
How do you find if you have 14.5 moles of N2 how many moles of H2 are theoretically needed to produce 22.5 moles of NH3 according to the reaction N2 plus 3H2 2NH3?
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------
If you have 14 grams of N2 how much NH3 can you make?
First you have to balance the equation N2 + H2 ---> NH3 N2 +3H2 ---> 2NH3 Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
How many grams of NH3 can be produced from 12.11 g H2?
N2(g) + 3H2-> 2NH3(g) This is the balanced equation Note the mole ratio between N2, H2 and NH3. It is 1 : 3 : 2 This will be important. moles N2 present = 28.0 g N2 x 1 mole N2/28 g = 1 mole N2 present moles H2 present = 25.0 g H2 x 1 mole H2/2 g = 12.5 moles H2 present Based on mole ratio, N2 is limiting in this situation because there is more than enough H2 but not enough N2. moles NH3 that can be produced = 1 mole N2 x 2 moles NH3/mole N2 = 2 moles NH3 can be produced grams of NH3 that can be produced = 2 moles NH3 x 17 g/mole = 34 grams of NH3 can be produced NOTE: The key to this problem is recognizing that N2 is limiting, and therefore limits how much NH3 can be produced.
