CH4 + Cl2 → CH3Cl + HCl - monohlor metan
CH3Cl + Cl2 → CHCl2 + HCl - dihlor metan
CHCl2 + Cl2 → CHCl3 + HCl - trihlor metan
CHCl3 + Cl2 → CCl4 + HCl - tetrahlor metan
Number of atoms in both side should be equal.Balanced equation is as follaws. CH4+2O2---->CO2+2H2O
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Ch4 + 4cl2 ---> ccl4 + 4 hcl
P4+Cl2 P4+Cl2
KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 After you balance it: 2KMnO4 + 16HCl = 5Cl2 + 8H2O + 2KCl + 2MnCl2
Cl2 + H2O = HOCl + HCl
For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl. H2 + Cl2 = 2 HCl
hcl
You start with methane (CH4 ) and chlorine ( Cl2) and react them thus:- CH4 + Cl2 → CH3Cl + HCl CH3Cl + Cl2 → CH2Cl2 + HCl CH2Cl2 + Cl2 → CHCl3 + HCl
Ch4 + 4cl2 ---> ccl4 + 4 hcl
CH4 + Cl2 → CH3Cl + HCl CH3Cl + Cl2 → CH2Cl2 + HCl CH2Cl2 + Cl2 → CHCl3 + HCl
Just replace one H and add a Cl (CH3Cl). In the next step replace another H by Cl. It's a chain reaction under sunlight: CH4+Cl2=CH3Cl+HCl CH3Cl+Cl2=CHCl2+HCL CH2Cl+Cl2=CHCl3+HCl CHCl3+Cl2=CCl4+HCl I'm sure now the structural formula will be apiece of cake.
P4+Cl2 P4+Cl2
3(Cl2) + 3(H2O) = 5(HCl) + 1(HClO3)
The chemical reaction is:CH4 + 4 Cl2 = CCl4 + 4 HCl
8H2S + 8Cl2 -------> S8 + 16HCl. Not happy about that "S8", should it just be "8S"?
KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 After you balance it: 2KMnO4 + 16HCl = 5Cl2 + 8H2O + 2KCl + 2MnCl2
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2
6NH4ClO4 + 10Al = 5Al2O3 + 3N2 + 6HCl + 9H2O