4KO2(S) + 2H2O(l) ----> 4KOH(aq) + 3O2(g)
There you are.
2H2 + O2 = 2H2O
does that make sense?
there are
4 H on the left
4 H on the right
2 O on the left
2 O on the right
get it? =]
2 in front of the H2 and a 2 in front of the H2O
2 H2 + O2 ----> 2 H2O
4ko2 + 2h2o -> 4koh + 3o2
All capitals. Site acting up again.
2 × h ₂ + o ₂ ➙ 2 × h ₂ o
The reaction is:4KO2 + 2H2O ---> 4KOH + 3O2
323.2 grams of KO2 is equal to 4.55 moles of KO2. Per the equation, 3.4125 moles of O2 is produced which is equal to 2.055 E24 molecules of oxygen. This means that every mg of KO2 produces 6.36 E18 molecules of O2.
The principal oxidation state of NA in NA2O2 and K in KO2 is +1
The thermal decomposition reaction is:2 KO2------------K2O2 + O20,2 moles of O2 are produced from o,4 moles KO2.
+3
The reaction is:4KO2 + 2H2O ---> 4KOH + 3O2
323.2 grams of KO2 is equal to 4.55 moles of KO2. Per the equation, 3.4125 moles of O2 is produced which is equal to 2.055 E24 molecules of oxygen. This means that every mg of KO2 produces 6.36 E18 molecules of O2.
KO2
The principal oxidation state of NA in NA2O2 and K in KO2 is +1
The thermal decomposition reaction is:2 KO2------------K2O2 + O20,2 moles of O2 are produced from o,4 moles KO2.
+3
The balanced equation is this: 2K + 2H2O --> 2KOH + H2
It is KO2 .
KO2, [O2-] being the superoxide anion.
Three potassium oxides are known: K2O, KO2, K2O2.
K + o2 = ko2
You would need 18 grams to get the requirement. Using a chemical equation can help to solve this for you.