There is no easy method to balancing equations, you just have to check each side of the equation to ensure that it has an equal number of each atom: 2K + 2H2O --------> H2 + 2KOH
There is no easy method to balancing equations, you just have to check each side of the equation to ensure that it has an equal number of each atom: 2K + 2H2O --------> H2 + 2KOH
There is no need to balance, BC the equation is already balanced. All that is occurring in the rxn is the removal of the proton from the acetic acid and the salt becoming water.
2ch3oh +3o2=2co2+4h2o
Co2 + 3h2 gives ch3oh + h2o
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
C2H6O + 3 O2 = 2 CO2 + 3 H2O
H2O + CO2 --> H2CO3 Also if you mix H2O with CO2(s) (common name dry ice) you get CO2 gas and an acidic CO2/H2O mixture.
This equation is C18H36 + 54 O2 = 18 CO2 + 18 H2O.
Co2 + 3h2 gives ch3oh + h2o
its balanced
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
2h2s+o2-->2h2o+co2
You mean balance it? 2C2H6 + 7O2 -> 4CO2 + 6H2O
CO2+H2O
NaHCO3 + HNO3--> NaNO3 + H2O + CO2
c2h5oh+h2o
NO. There is no chlorine on the reactant side, so it cannot be balanced.
3no2 h2o --> 2hno3 no
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
N2O5 + H2O = 2 HNO3